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6610 GATEWAY TER 2020-03-06
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6610 GATEWAY TER 2020-03-06
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3/6/2020 11:28:38 AM
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3/6/2020 11:24:18 AM
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Street Name
GATEWAY TER
Street Number
6610
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GK Structural Engineering,LLC Project Title: DeL Resid Fire Repair <br /> 147031st Lane NE,#205 Engineer: JG <br /> ' Duvall,WA 98019 Project ID: YR10-18-037 <br /> 425.318.6049 Project Descr: <br /> www.gkstructural.com <br /> Wood Beam File C:1—GKS-1\—PRO-11-YR10-11YRBD5C-11-CALCS-11structcaics(DeLeon) 18.037.ec6. <br /> Software copyright ENERCALC,INC.1983-2018,Build:10.18.8.25 . <br /> Lic.#:KW-06008655 Licensee:GK STRUCTURAL ENGINEERING LLC <br /> Description: (N)Relocated Living Room Window Header <br /> CODE REFERENCES <br /> Calculations per NDS 2015, IBC 2015, CBC 2016,ASCE 7-10 <br /> Load Combination Set:ASCE 7-10 <br /> Material Properties <br /> Analysis Method: Allowable Stress Design Fb+ 850.0 psi E:Modulus of Elasticity <br /> Load Combination ASCE 7-10 Fb- 850.0 psi Ebend-xx 1,300.0 ksi <br /> Fc-Pill 1,300.0 psi Eminbend-xx 470.0 ksi <br /> Wood Species : Hem Fir Fc-Perp 405.0 psi <br /> Wood Grade : No.2 Fv 150.0 psi <br /> Ft 525.0 psi Density 26.830pcf <br /> Beam Bracing : Completely Unbraced <br /> D(0.189)S(0.3375) <br /> o D(T02) o 0 <br /> o 0 0 0 <br /> X <br /> Alik 6 1 <br /> 4x8 <br /> Span=5.50 ft <br /> I <br /> Applied Loads Service loads entered.Load Factors will be applied for calculations. <br /> Beam self weight calculated and added to loads <br /> Uniform Load: D=0.010 ksf, Tributary Width=2.0 ft,(Wall DL) <br /> Uniform Load: D=0.0140, S=0.0250 ksf, Tributary Width=13.50 ft,(Roof DL+SL) <br /> DESIGN SUMMARY Design OK <br /> Maximum Bending Stress Ratio = 0.649 1 Maximum Shear Stress Ratio = 0.406 : 1 <br /> Section used for this span 4x8 Section used for this span 4x8 <br /> fb:Actual = 815.75psi fv:Actual = 69.99 psi <br /> FB:Allowable = 1,257.80 psi Fv:Allowable = 172.50 psi <br /> Load Combination +D+S+H Load Combination +D+S+H <br /> Location of maximum on span = 2.750ft Location of maximum on span = 4.898 ft <br /> Span#where maximum occurs = Span#1 Span#where maximum occurs = Span#1 <br /> Maximum Deflection <br /> Max Downward Transient Deflection 0.048 in Ratio= 1364>=600 <br /> Max Upward Transient Deflection 0.000 in Ratio= 0<600 <br /> Max Downward Total Deflection 0.079 in Ratio= 835>=480 <br /> Max Upward Total Deflection 0.000 in Ratio= 0<480 <br /> . 034 N) <br /> 4'° <br /> F WAS�4^1 <br /> w <br /> vow Atir <br /> IC, �#.;70.-_ <br /> itv Ari: <br /> -4, *.t .*401 A <br /> A /ONra VtAG - <br />
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