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BASE SLIDING <br /> Sliding at the base is checked at the block to leveling pad interface between the base block and the leveling <br /> pad. Sliding is also checked between the leveling pad and the foundation soils. <br /> Forces Resisting sliding =W1 +W2+ Pay <br /> 5,076 + 362 + 1,849 N =7,287 ppf <br /> Resisting force at pad = 0.8 N tan(slope) + intercept <br /> 7,287 x 0.8 tan(40.0) Rf1 =5,348 <br /> where L is the base block width <br /> With tilt, the resisting force is'SumV*cos(tilt)'+ Rf*sin(tilt) + Df*sin(tilt) <br /> because the unit is sliding 'upslope'. The program also checks sliding through the pad, <br /> taking the minimum value for Re. The result is correct, the equation shown is not complete. <br /> Friction angle is the lesser of the leveling pad and Fnd cp=34.00 deg <br /> N1 includes N (the leveling pad) + leveling pad (LP) <br /> 7,287+ 336 N1 = 7,623 ppf <br /> Passive resistance is calculated using kp= (1 + sin(34))/(1 -sin(34)) kp= 3.54 <br /> Pressure at top of resisting trapezoid, d1 = 1.80 Fp1 = 795.85 <br /> Pressure at base of resisting trapezoid, d2 = 2.79 Fp2 = 1,233.91 <br /> Depth of trapezoid depth = 0.99 <br /> Pp= (Fp1 + Fp2)/2 *depth 1,005.49 <br /> Resisting force at fnd = (N1 tan(phi)+ c L) + Pp <br /> 7,623 x tan(34) + 0 x 5.42 + 1,005 Rf2 =6,147 <br /> where LP= Ivl pad thickness* 130pcf*(L+ Ivl pad thickness/2) <br /> [the value printed is the minimum of sliding through the leveling pad or the foundation soil. <br /> Driving force is the horizontal component of Pah <br /> 2,760 Df=2,760 <br /> FSsi = Rf/Df FSsl=1.95/2.23 <br /> (// 9' e7') ) <br /> UltraWali 5.0.18138 Pag <br />