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COOLING <br />1. Method for obtaining system cooling and heating capacity: <br />To obtain the system cooling and heating capacity and the electrical characterlstla of the outdoor unit, first add up the nothings <br />of all the Indoor units connected to the outdoor unit (see table below). For Standard Capacity Diagram, please refer to the MR -C <br />Technical & Service Manual. <br />(1) Capacity of Indoor unit <br />Ab„Iodl!�Wnsuhran <br />nnAA <br />mi 0a <br />Wool 09 <br />Model 12 Model 15 <br />MWBI 13 <br />Wool 24 <br />MWrl 30 <br />Model 35 <br />M seM¢ <br />WWIf. Y9oay <br />IkBWITI <br />a.0 <br />a.0 <br />12.0 140 <br />15.P° <br />17'2•3 <br />19.01 <br />22.5 <br />— <br />— <br />P ¢«le¢ <br />120 <br />1 <br />6.No <br />35.0 <br />9F2 <br />e.1 <br />115 14A <br />17.2 <br />AZ <br />I <br />fra <br />111 <br />MJZ <br />120 <br />1B0 <br />(L0 <br />90.0 <br />ea0 <br />••M.ors...aMazr,EurM <br />'r TrerLeebM9LL+F/ Bret. <br />dd sample cak lM n <br />1 Sy&am Wmgm M from Indoor and WIMtt unlr (M IMB aYmi Me WWI aapaary 0the IWMr units IS greabr Man 0d1 M <br />Me wool unit) <br />-Cwdaruna M%Z-SCARNAl <br />•Indoor unit MSZ GEMNA-21 MSZ-F11soul =2 <br />2 Acuvdlrq to Me mrd 1110na In 1 , to total Wooly of Me Indoor unit will od'.90 - 21150 = 2 = a 0 <br />3 Tne W1IMmp figures are OMaimd Iran the 10.a WWI capacty M Indoor unit, raldnng Me eMMed Muctur dagmm F <br />'4J3. MX C42MHZ euofin0> aM-43 M%Z-SGRNAHZ<Isdr <br />Capmry(MBNN) 0 i unit not mnsumplod lko)Cr Creditor unit current 230V <br />Cooing XeatM9 Cwling Heating Cooling Ibtoo <br />A 42.0 B 4B0 345 437 15n 1931 <br />2. Method for obtaining the Madng and cooling capacity of an Indoor unit <br />mutlelu0ary <br />(1)meuw011yoreechlndoorunx(M-Ma Capua A («B)o <br />1<Ul model gOelMolall indoor uNb <br />12) Sample colonel orming the syclem described Waves In 4L1.0)(: <br />Doctors =Doting: <br />• The trial tunnel riu aay M We Indoor unit is, <br />90+24150+2=00 WITWT <br />Thermos, Mn upacny of MSZGEOMaA and <br />MSZfH 1 all got the unwound as fdlws by <br />uarg Me 1mmJa F 4.1-2. (1): <br />Model09 =42.0 = 9.0 =T.88 NBTUM <br />48.0 <br />Model 15=4EO a 15'0 =13.13 Wall <br />48.0 <br />goring hutln9: <br />The Wlel Wood ceuary W Ind" unit Is: <br />109 c 2 c 190 c 2. 57 B Will <br />TheMOm the Went 0 MSZGE09Wr and Msl <br />Fill Wit all he ulWetd as fouowe by using the <br />lmmule in a1-2. (1). <br />Ab]tl25=4e13= 1 9=culiwl <br />Me <br />W a W-48.0 v 1 0.1495 FBTUM <br />5)e <br />0 N17 Mp b,3N Ebue Us. Inn. <br />