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ITitle Block Line 1 Project Title: <br /> You can change this area Engineer: <br /> using the"Settings"menu item Project ID: <br /> 1 and then using the"Printing& Project Descr: <br /> Title Block"selection, <br /> Title Block Line 6 Printed:22 SEP 2021, 2:54PM <br /> ood �iph t1 n file Rivers until r ta2 <br /> 'Software c P19fiitgNEBG C ING't,.-. ---E ld i2�UB*d <br /> DESCRIPTION: Bottom-DF(NEW) <br /> Code References <br /> Calculations per NDS 2018, IBC 2018,CBC 2019,ASCE 7-16 <br /> Load Combinations Used :ASCE 7-16 <br /> General Information <br /> Analysis Method: Allowable Stress Design Wood Section Name 6x6 <br /> End Fixities Top Free, Bottom Fixed Wood Grading/Manuf. Graded Lumber <br /> I <br /> Overall Column Height 5.67 ft Wood Member Type Sawn <br /> Used for non-slender calculations Exact Width <br /> Wood Species Douglas Fir-Larch 5.50 in Allow Stress Modification Factors <br /> Exact Depth 5.50 in Cf or Cv for Bending 1.0 <br /> Wood Grade No.1 Area 30.250 in^2 Cf or Cv for Compression 1.0 <br /> Fb+ 1,200.0 psi Fv 170.0 psi lx 76,255 in^4 Cf or Cv for Tension 1.0 <br /> Fb- 1,200.0 psi Ft 825.0 psi ly 76.255 in^4 Cm:Wet Use Factor 1.0 <br /> Fc Prll 1,000.0 psi Density 31.210 pcf Incising Factors r_t.:Temoermure Factor 1.0 <br /> Fc-Perp 625.0 psi Factors_. <br /> for Bending 0.80 Cfu:Flat Use Factor 1.0 <br /> E:Modulus of Elasticity... x-x Bending y-y Bending Axial for Elastic Modulus 0.95 Kf:Built-up columns 1.0 s?:�_s.a <br /> Basic 1,600.0 1,600.0 1,600.0 ksi Use Cr Cr::Repetitive? No <br /> Minimum 580.0 580.0 Brace condition for deflection(buckling)along columns: <br /> I <br /> X-X(width)axis: Unbraced Length for buckling ABOUT Y-Y Axis=5.67 ft,K=1. <br /> Y-Y(depth)axis: Unbraced Length for buckling ABOUT X-X Axis=5.67 ft,K=1. <br /> Applied Loads Service loads entered.Load Factors will be applied for calculations. <br /> Column self Weight included:37.174 lbs*Dead Load Factor <br /> IAXIAL LOADS. .. <br /> Axial Load at 5.670 ft,D=1.950,L=2.990,S=1.125 k <br /> BENDING LOADS... <br /> Lat.Point Load at 5.830 ft creating Mx-x,E=0.8530 k <br /> IDESIGN SUMMARY <br /> Bending&Shear Check Results <br /> PASS Max.Axial+Bending Stress Ratio = 0.9875 1 Maximum SERVICE Lateral Load Reactions.. <br /> 1 Load Combination +D+0 0.0 k Bottom along Y-Y 0.8534 k <br /> Governing NDS Forumld 1 Comp+Mxx,NDS Eq.3.970E Top along Y-Y <br /> 3 Top along X-X 0.0 k Bottom along X-X 0.0 k <br /> Location of max.above base 0.0 ft Maximum SERVICE Load Lateral Deflections... <br /> At maximum location values are... Along Y-Y 0.7688 in at 5.670 ft above base <br /> 1 Applied Axial Applied Mx 1.987 k <br /> -3.386 k-ft for load combination: E Only <br /> Applied My 0_0 k-ft Along X-X 0.0 in at 0.0 ft above base <br /> Fc:Allowable 1,070.37 psi for load combination:nia <br /> I <br /> Other Factors used to calculate allowable stresses... <br /> PASS Maximum Shear Stress Ratio= 0.1361 :1 Bending Compression Tension <br /> Load Combination +D+0.70E <br /> Location of max.above base 5.670 ft <br /> Applied Design Shear 29.608 psi <br /> Allowable Shear 217.60 psi <br /> Load Combination Results <br /> I <br /> Maximum Axial+Bending Stress Ratios Maximum Shear Ratios <br /> Load Combination C D C p Stress Ratio Status Location Stress Ratio Status Location <br /> D Only 0.900 0.919 0.09928 PASS 0.0 ft 0.0 PASS 5.670 ft <br /> +D+L 1.000 0.908 0.2265 PASS 0.0 ft 0.0 PASS 5.670 ft <br /> +D+S 1.150 0.891 0.1255 PASS 0.0 ft 0.0 PASS 5.670 ft <br /> +D+0.750L 1.250 0.880 0.1590 PASS 0.0 ft 0.0 PASS 5.670 ft <br /> +D+0.750L+0.7505 1.154 0.891 0.2046 PASS 0.0 ft 0.0 PASS 5.670 ft <br /> +0.60D 1.600 0.836 0.03682 PASS 0.0 ft 0.0 PASS 5.670 ft <br /> +D+0.70E 1.600 0.836 0.9875 PASS 0.0 ft 0.1361 PASS 5.670 ft <br /> +D+0.750L+0.7505+0.5250E 1.600 0.836 0.8001 PASS 0.0 ft 0.1021 PASS 5.670 ft <br /> +0.60D+0.70E 1.600 0.836 0.9729 PASS 0.0 ft 0.1361 PASS 5.670 ft <br /> 1 89 <br />