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3301 SEAWAY BLVD 120 TERRA POWER 2024-10-25
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3301 SEAWAY BLVD 120 TERRA POWER 2024-10-25
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Last modified
10/25/2024 11:56:25 AM
Creation date
7/22/2024 9:58:52 AM
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Address Document
Street Name
SEAWAY BLVD
Street Number
3301
Unit
120
Tenant Name
TERRA POWER
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Structural <br /> Engineering & Design Inc. <br /> 1815 Wriciht Ave La Verne, CA 91750 Tel: 909.596,1351 Fax: 909.596,7186 <br /> By: Bob S Project: Terra Power Project#: 24-0325.11 <br /> BEAM Configuration:TYPE 1 SELECTIVE RACK <br /> RMI Section 5,2,PT II <br /> Section <br /> Beam= SpaceRak SB306M 3 in.x 0.06 in <br /> Ix=Ib= 0.725 inA4 2,501n <br /> Sx= 0.444 inA3 <br /> t= 0.060 in E= 29500 ksi 1.63 in <br /> Fy=Fyv= 55 ksi F= 300.0 ___ <br /> Fu=Fuv= 65 ksi L= 96 in r ,II( <br /> Fya=59.0 ksi Beam Level= 1 1.625 In <br /> P=Product Load= 2,800 lb/pair <br /> D=Dead Load= 75 lb/pair 3,000 <br /> I i 0.060 in <br /> 1.Check Bending Stress Allowable Loads <br /> Mcenter=F*Mn= W*L*W*Rm/8 <br /> W=LRFD Load Factor= 1.2*D+ 1.4*P+1.4*(0.125)*P RM%22,item 8 <br /> FOR DL=24/o of PL, <br /> W= 1,599 <br /> IIIIIIIIIIIIIIIIIIIIIIII111111Ii111111111I1111I1111111II <br /> Rm= 1- [(2*F*L)/(6*E*Ib+3*F*L)] = I► u <br /> 1 (2*300*96 in)/[(6*29500 ksl*0.725 inA3)+(3*300*96 In)] <br /> = 0.732 <br /> if F= 0.95 .dd•att <br /> Then F*Mn=F*Fya*Sx= 24.87 in-k <br /> Thus,allowable load <br /> per beam pair=W= F*Mn*8*(#of beams)/(L*Rm*W) �5► t : <br /> = 24.87 in-k*8*2/(96in*0.732*1,599) Length <br /> = 3,542 lb/pair allowable load based on bending stress •,—s — <br /> Mend=W*L*(1-Rm)/8 <br /> (3542 lb/2) *96 in*(1-0.732)/8 <br /> = 5,696 in-lb @ 3542 lb max allowable load <br /> = 4,502 in-lb @ 2800 lb imposed product load <br /> 2.Check Deflection Stress Allowable Loads <br /> Dmax= Dss*Rd <br /> Rd= 1-(4*F*L)/(5*F*L+ 10*E*Ib) Allowable Deflection= L/180 <br /> = 1-(4*300*96 in)/[(5*300*96 in)+(10*29500 ksi*0.725 inA4)] = 0.533 in <br /> = 0.678 In Deflection at imposed Load= 0.511 in <br /> if Dmax= L/180 Based on L/180 Deflection Criteria <br /> and Dss= 5*W*LA3/(384*E*Ib) <br /> L/180= 5*W*LA3*Rd/(384*E*Ib*#of beams) <br /> solving for W yields, <br /> W= 384*E*I*2/(180*5*LA2*Rd) <br /> = 384*0.725 inA4*2/[180*5*(96 in)A2*0.678) <br /> = 2,921 lb/pair allowable load based on deflection limits <br /> Thus,based on the least capacity of item 1 and 2 above: Allowable load= 2,921 lb/pair <br /> Imposed Product Load= 2,800 lb/pair <br /> 'Beam Stress= 0.96 Beam at Level 1 <br />
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