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3301 SEAWAY BLVD 120 TERRA POWER 2024-10-25
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3301 SEAWAY BLVD 120 TERRA POWER 2024-10-25
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Last modified
10/25/2024 11:56:25 AM
Creation date
7/22/2024 9:58:52 AM
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Address Document
Street Name
SEAWAY BLVD
Street Number
3301
Unit
120
Tenant Name
TERRA POWER
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• <br /> . Structural <br /> Engineering & Design Inc. <br /> 1815 Wright Ave La Verne, CA 91750 Tel: 909.596.1351 Fax: 909.596.7186 <br /> By: Bob S Project: Terra Power Project#:24-0325-11 <br /> Transverse Brace Configuration:TYPE 1 SELECTIVE RACK <br /> Section Properties <br /> Diagonal Member= Sperack 1-1/2x1-1/4x14ga Horizontal Member= Sperack 1-1/2x1-1/4x14ga <br /> --- --- ---Area= 0.292 in"2- - - Area= 0.292in^2-- . - - - - -— - -- --- -- ---- <br /> I.500 in <br /> r'min= 0.430 in r min= 0,430 In 14. 1.500 in <br /> Fy= 55,000 psi ���..�'+--- " Fy= 55,000 psi <br /> K= 1.0 I K= 1.0 <br /> I <br /> 0.075 in ( 1.250 m in + 1.250 <br /> S2C= 1.92 0.075 <br /> 1 _ L <br /> Frame Dimensions <br /> Bottom Panel Height=H= 54.0 In Clear Depth=D-B*2=.36.0 in <br /> Frame Depth=D= 42.0 In X Brace= NO <br /> Column Width=B= 3.0 in rho= 1.00 <br /> Diagonal Member • <br /> 0 <br /> Load Case 6::(1 .85+0,14Sds)*B*P+[0.7*rho*EJ<=1.0,ASL)Method 14 I o —►! <br /> Vtransverse= 1,565 lb Vb I <br /> Vb=Vtransv*0.7*rho= 1565 lb*0.7* 1 (kl/r)= (k*Ldiag)/r min <br /> = 1,096 lb = (1 x 60 in/0.43 in) <br /> Ldiag [(D-B*2)^2+(H-6")^21^1/2 = 139.5 in Ldiag <br /> = 60.0 in Fe= pi^2*E/(kl/r)^2 H <br /> Pmax= V*(Ldiag/D)* 0.75 = 14,961 psi it Pmax <br /> = 1,174 lb d—,... <br /> axial load on diagonal brace member Since Fe<Fy/2, 3^ <br /> Pn= AREA*Fn Fn= Fe B <br /> = 0.292 in^2* 14961 psi = 14,961 psi Typical Panel <br /> = 4,369 lb Conflauration <br /> Pallow= Pn/n Check.End Weld <br /> = 4369 lb/1.92 Lweld= 3.0 in <br /> = 2,275 lb Fu= 65 ksi <br /> tmin= 0.075 in <br /> Pn/Pallow= 0.52 <= 1.0 OK Weld Capacity= 0.75*tmin*L*Fu/2.5 <br /> = 4,388 lb OK <br /> Horizontal brace <br /> Vb=Vtransv*0.7*rho= 1,096 lb <br /> (kl/r)= (k*Lhoriz)/r min Fe= pi^2*E/(kl/r)^2 Fy/2= 27,500 psi <br /> = (1 x 42 in)/0.43 in = 30,502 psi <br /> = 97.7 in <br /> Since Fe>Fy/2,Fn=Fy*(1-fy/4fe) Pn= AREA*Fn Pallow= Pn/S2c <br /> = 30,207 psi = 0.2921n^2*30207 psi = 8820 lb/1.92 <br /> = 8,820 lb = 4,594 lb <br /> Pn/Pallow= 0.24 <= 1.0 OK <br /> type 2 select-SG-Terra.xis Page ( 6 of (y 3/26/2024 <br />
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