1504 GRAND AVE 2024-11-14 - Laserfiche WebLink

• Wood Beam File=S:\Jobs1s181s1803\s1803016-1504 Grand Ave\wo xxxxxx\_enercalc tnb 180131_.ec6 ENERCALC,INC.1983-2017,Build:6.17.2.28,Ver:6.17.2.28 Lic.#:KW-06006655 Licensee:SOUND STRUCTURAL SOLUTIONS Description: 2x2 Pickets CODE REFERENCES Calculations per NDS 2015, IBC 2015, CBC 2016,ASCE 7-10 Load Combination Set: IBC 2015 Material Properties Analysis Method: Allowable Stress Design Fb-Tension 850.0 psi E:Modulus of Elasticity Load Combination IBC 2015 Fb-Compr 850.0 psi Ebend-xx 1,300.0 ksi Fc-Prll 1,300.0 psi Eminbend-xx 470.0 ksi Wood Species : Hem Fir Fc-Perp 405.0 psi Wood Grade : No.2 Fv 150.0 psi Ft 525.0 psi Density 26.830 pcf Beam Bracing : Completely Unbraced L(0.05) X X X. X 1.50X 1.50 Span=2.10ft Applied Loads Service loads entered. Load Factors will be applied for calculations. Uniform Load: L=0.050 ksf, Tributary Width=1.0 ft,(Lateral railing pressure) DESIGN SUMMARY Desi•n OK Maximum Bending Stress Ratio = 0.629: 1 Maximum Shear Stress Ratio = 0.206 : 1 Section used for this span 1.50 X 1.50 Section used for this span 1.50 X 1.50 fb:Actual = 588.00 psi fv:Actual = 30.91 psi FB:Allowable = 935.00 psi Fv:Allowable = 150.00 psi Load Combination +D+L+H Load Combination +D+L+H Location of maximum on span = 1.050ft Location of maximum on span = 0.000ft Span#where maximum occurs = Span#1 Span#where maximum occurs = Span#1 Maximum Deflection Max Downward Transient Deflection 0.040 in Ratio= 628>=360 Max Upward Transient Deflection 0.000 in Ratio= 0<360 Max Downward Total Deflection 0.040 in Ratio= 628>=180 Max Upward Total Deflection 0.000 in Ratio= 0<180 Overall Maximum Deflections Load Combination Span Max.""Defl Location in Span Load Combination Max."+"Defl Location in Span L Only 1 0.0401 1.058 0.0000 0.000 2L\\2a