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1420 80TH ST SW NORTHWEST PUMP & EQUIPMENT CO 2024-12-30
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1420 80TH ST SW NORTHWEST PUMP & EQUIPMENT CO 2024-12-30
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Last modified
12/30/2024 3:27:31 PM
Creation date
12/1/2024 7:42:59 AM
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Street Name
80TH ST SW
Street Number
1420
Tenant Name
NORTHWEST PUMP & EQUIPMENT CO
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Structural <br /> i <br /> Engineering & Design I nc. <br /> i! <br /> r' 1815 Zt=Ave La Verne, A 91750 T I OA 96 1 51 Fax OA A6 7186 <br /> By: NIHAL Project: NORTHWEST PUMP Project#: <br /> i <br /> BEAM Contiguration:TYPE A 5 <br /> RMI Section 5.2, PT II <br /> Section <br /> Beam=SpaceRak SB376M 3.75 in x 0.06 in <br /> Ix=Ib= 1.253 in^4 2.50 in <br /> Sx= 0.627 in^3 <br /> t= 0.060 in E= 29500 ksi 1.63 in J <br /> Fy=Fyv= 55 ksi F= 300.0 T <br /> Fu=Fuv= 65 ksi L= 96 in <br /> Fya 59.0 ksi Beam Level= 1 1.625 in <br /> P=Product Load 4,000 lb/pair <br /> D=Dead Load= 75 lb/pair 3.750 in <br /> 0.060 in <br /> 1.Check Bending Stress Allowable Loads <br /> Mcenter=F*Mn= W*L*W*Rm/8 <br /> W=LRFD Load Factor= 1.2*D+ 1.4*P+1.4*(0.125)*P RMI2.2,item 8 <br /> FOR DL=2%of PL, <br /> W= 1.599 <br /> Rm= 1-[(2*F*L)/(6*E*Ib+3*F*L)] <br /> 1-(2*300*96 in)/[(6*29500 ksi*1.253 in^3)+(3*300*96 in)] -' --------- - <br /> = 0.813 <br /> If F= 0.95 P.nauce <br /> Then F*Mn=F*Fya*Sx= 35.13 in-k <br /> Thus,allowable load = <br /> per beam pair=W= F*Mn*8*(#of beams)/(L*Rm*W) ;Beam <br /> = 35.13 in-k*8*2/(96in*0.813 * 1.599) Lernglh <br /> = 4,504 Ib/pair allowable load based on bending stress my 9T, <br /> Mend= W*L*(1-Rm)/8 <br /> = (4504 Ib/2)*96 in* (1-0.813)/8 <br /> = 5,053 in-lb @ 4504 lb max allowable load <br /> = 4,488 in-lb @ 4000 lb imposed product load <br /> 2.Check Deflection Stress Allowable Loads <br /> Dmax= Dss*Rd <br /> Rd= 1-(4*F*L)/(5*F*L+ 10*E*Ib) Allowable Deflection= L/180 <br /> = 1-(4*300*96 in)/[(5*300*96 in)+(10*29500 ksi*1.253 in^4)] = 0.533 in <br /> = 0.776 in Deflection at imposed Load= 0.484 in <br /> if Dmax= L/180 Based on 41180 Derlection Criteria <br /> and Dss= 5*W*L^3/(384*E*Ib) <br /> L/180= 5*W*L^3*Rd/(384*E*Ib*#of beams) <br /> solving for W yields, <br /> W= 384*E*I*2/(180*5*L^2*Rd) <br /> = 384*1.253 in^4*2/[180*5*(96 in)^2*0.776) <br /> = 4,410 Ib/pair allowable load based on deflection limits <br /> Thus,based on the least capacity of item 1 and 2 above: Allowable load= 4,410 lb/pair <br /> Imposed Product Load= 4,000 lb/pair <br /> Beam Stress= 0.91 Beam at Level 1 <br /> ��2 <br />
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