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• • Project Title: <br /> t <br /> Engineer: <br /> Project ID: <br /> UMLAUF ENGINEERS Project Descr: <br /> Printed: 8 APR 2021, 7:01PM <br /> Wood Column File:Zap.ec6 <br /> Software copyright ENERCALC,INC.1983-2020,Build:12.20.8.24 <br /> Lic.#:KW-06011909 L2 Engineers <br /> DESCRIPTION: P1 <br /> Code References <br /> Calculations per NDS 2018, IBC 2018, CBC 2019,ASCE 7-16 <br /> Load Combinations Used :ASCE 7-16 <br /> General Information <br /> Analysis Method: Allowable Stress Design Wood Section Name 6x6 <br /> End Fixities Top&Bottom Pinned Wood Grading/Manuf. Graded Lumber <br /> Overall Column Height 10 ft Wood Member Type Sawn <br /> or; slender calculations) Exact Width 5.50 in Allow Stress Modification Factors <br /> Wood Species Douglas Fir-Larch Exact Depth <br /> Wood Grade No.1 p 5.50 in Cf or Cv for Bending 1.0 <br /> Fb+ 1,200.0 psi Fv 170.0 psi Area 30.250 inA2 Cf or Cv for Compression 1.0 <br /> Ix 76.255 in^4 Cf or Cv for Tension 1.0 <br /> Fb- 1,200.0 psi Ft 825.0 psi ly :Wet Use Factor 1.0 <br /> Fc-Prll 1,000.0 psi Density 31.210 pcf y 76.255 inM 4 <br /> Fc-Perp 625.0 psi Ct:Temperature Factor 1.0 <br /> Cfu:Flat Use Factor 1.0 <br /> E:Modulus of Elasticity... x-x Bending y-y Bending Axial Kf:Built-up columns 1.0 NDS 15.3.2 <br /> Basic 1,600.0 1,600.0 1,600.0 ksi Use Cr:Repetitive? No <br /> Minimum 580.0 580.0 Brace condition for deflection(buckling)along columns: <br /> X-X(width)axis: Unbraced Length for buckling ABOUT Y-Y Axis=10 ft,K=1.0 <br /> Y-Y(depth)axis: Unbraced Length for buckling ABOUT X-X Axis=10 ft,K=1.0 <br /> Applied Loads Service loads entered. Load Factors will be applied for calculations. <br /> Column self weight included:65.563 lbs*Dead Load Factor <br /> AXIAL LOADS.. . <br /> Mezzanine:Axial Load at 10.0 ft,D=5.0,L=14.0 k <br /> DESIGN SUMMARY <br /> Bending&Shear Check Results <br /> PASS Max.Axial+Bending Stress Ratio = 0.9114:1 Maximum SERVICE Lateral Load Reactions.. <br /> Load Combination +D+L Top along Y-Y 0.0 k Bottom along Y-Y 0.0 k <br /> Governing NDS Forumla Comp Only,fc/Fc' Top along X-X 0.0 k Bottom along X-X 0.0 k <br /> Location of max.above base 0.0 ft Maximum SERVICE Load Lateral Deflections... <br /> At maximum location values are... Along Y-Y 0.0 in at 0.0 ft above base <br /> Applied Axial 19.066 k for load combination: n/a <br /> Applied Mx 0.0 k-ft Along X-X 0.0 in at 0.0 ft above base <br /> Fc:Allowable 691.51 <br /> Applied My 0.0 for load combination:n/a <br /> psi <br /> si <br /> Other Factors used to calculate allowable stresses... <br /> PASS Maximum Shear Stress Ratio= 0.0:1 Bending Compression Tension <br /> Load Combination +0.60D <br /> Location of max.above base 10.0 ft <br /> Applied Design Shear 0.0 psi <br /> Allowable Shear 272.0 psi <br />