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• • . <br /> "FOOTINGS.xls" Program <br /> Version 3.8 <br /> Results: Nomenclature for Biaxial Eccentricity: <br /> Total Resultant Load and Eccentricities: Case 1: For 3 Corners in Bearing <br /> 3Pz= -182.82 kips (Dist.x>L and Dist.y>B) <br /> ex= 0.01 ft.(<=L/6) l< Dist.x <br /> ey=_ -3.00 _ft.(>B/6) --_ Pmax <br /> Brg. Ly A <br /> Overturning Check: <br /> EMrx= 822.67 ft-kips <br /> EMox= 547.56 ft-kips <br /> FS(ot)x= 1.502 >=1.5 J, Dist y <br /> EMry= 2467.67 ft-kips Line of zero <br /> EMoy= 1.25 ft-kips pressure i(Brg. Lx,. <br /> FS(ot)y= 1975.850 >. 1.5 <br /> Sliding Check: Case 2: For 2 Corners in Bearing <br /> Pass(x) = 26.05 kips (Dist.x>L and Dist.y<=B) <br /> Frict(x)= 73.13 kips Dist.x <br /> FS(slid)x= 1983.517 >=1.5 �`___ )1 Pmax <br /> Pass(y) = 78.15 kips $ Brg. Ly1 A <br /> Frict(y)= 73.13 kips <br /> FS(slid)y= 2.732 >=1.5 Dist.y <br /> Brg. Ly2 <br /> Uplift Check: <br /> EPz(down)= -182.82 kips Line of zero <br /> EPz(uplift)= 0.00 kips pressure <br /> FS(uplift) = N.A. <br /> Bearing ng Leth and%Bearing Area: Case 3: For 2 Corners in Bearing <br /> Dist. x= 12163.495 ft. (Dist.x<=L and Dist.y>B) <br /> Dist. y= 4.505 ft. I` Dist.x <br /> Brg. Ly1 = 4.495 ft. Brg. Lx2 Pmax <br /> A <br /> Brg. Ly2= 4.505 ft. <br /> %Brg.Area= 50.00 % <br /> Biaxial Case= Case 2 6*ex/L+6*ey/B=2.002 <br /> Gross Soil Bearing Corner Pressures: Dist.y <br /> Pi = 3.013 ksf Line of zero <br /> P2= 0.000 ksf pressure Brg.Lx1 <br /> P3= 0.000 ksf I` ' <br /> P4= 3.006 ksf <br /> Case 4: For 1 Corner in Bearing <br /> (Dist.x<=L and Dist.y<=B) <br /> P3=0 k P2=0 ksf <br /> I' Dist.x I <br /> BBrg.Lx >1 Pmax A <br /> P4=3.006 ksf L P1=3.013 ksf <br /> CORNER PRESSURES Dist.y <br /> Brg. Ly <br /> Maximum Net Soil Pressure: Line of zero <br /> Pmax(net)= Pmax(gross)-(D+T)*ys pressure , <br /> Pmax(net)= 2.531 ksf <br /> Comments: <br /> 2 of 2© 4/26/2023 1:33 PM <br />