Laserfiche WebLink
• <br /> PROJECT NAME: HULTS RESIDENCE <br /> JOB: X10-2854 <br /> d= tf- 3 in cover- 1/2 in bar dia = 12.00 in - 3"- 1/2" =8.50 in <br /> Distance to critical section for shear, Ls <br /> LS= L/2 - c,/2 - d=2.20- 11.00/(2x 12)- 8.50/12 =0.O0ft <br /> Factored pressure at critical shear location,pu <br /> pu=p„max(L-x- Ls)/(L-x) = 2216(2.20- 1.10-0.00)/(2.20- 1.10) =2216 psf <br /> Factored load at critical shear location, Vu <br /> Vu=pu-shear loc(B x Ls) = 2216(2.20)(0.00) = 0 lbs <br /> Factored load at critical shear location, Vu <br /> (I) V,=(I) (2f,1/2 bW d) = 0.85[2(2500)2(2.20'x 12)(8.50)= 19074 lbs <br /> (4) Vc= 19074 lb)> (Vu= 0 lb) OK <br /> Check two-way shear <br /> 7 Y/ T1Ztt'rlThRY <br /> I l s AG.felloACKIL <br /> IvCi <br /> c, +d - 1-s <br /> P. r <br /> ?�i5ti P ,c <br /> rWb-WAY SAG^K <br /> Distance to critical section for shear, Ls <br /> Ls= L/2 -c1/2 - d/2 = 2.20- 11.00/(2x 12) - 1/2[8.50/12] = 0.29 ft <br /> Factored pressure at critical shear location,pu <br /> pu=p max(L-x- Ls)/(L-x) = 2216(2.20- 1.10-0.29)/(2.20 - 1.10) = 1637 psf <br /> Length of critical perimeter, bo <br /> b0=4[c, + 2(d/2)] = 11.00 +2[8.50/2] = 78.00 in. <br /> Two-way shear, Vu <br /> Vu=pu[B x L- ((c1+d)112)2] = 1637[2.20 x 2.20- ((11.00+8.50)/12)2]=3600 lbs <br /> CUSTOM DESIGN & ENGINEERING, INC. <br /> October 20, 2021 Page 11 / 17 <br /> Copyright©2021 Custom Design&Engineering,Inc.All rights reserved. <br />