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PROJECT NAME: HULTS RESIDENCE ADDITION <br /> JOB: X10-2854 <br /> ->Distributive load on beam, w0 - from level <br /> ->From location 6.29 ft to 0.00 ft <br /> Compute typical distributive loads <br /> Joist cantilever span 1, a = 0.00 ft <br /> Joist cantilever span 2, c = 0.00 ft <br /> bl = L1 - a - c = 20.12 - 0.00 - 0.00 = 20.12 ft <br /> b2 = L2 - a - c = 20.12 - 0.00 - 0.00 = 20.12 ft <br /> wi or w2 = load, psf x L x (L - 2 x c) / (2 x bl or b2) <br /> wS = 25.00 psf x 20.12 ft x (20.12 ft - 2 x 0.00) / (2 x 20.12) = 251.56 lb/ft <br /> wD = 15.00 psf x 20.12 ft x (20.12 ft - 2 x 0.00) / (2 x 20.12) = 150.94 lb/ft <br /> ->Computed moments and shears (Factored) : <br /> Max shear = 1266 lbs D + S (2.4-3) <br /> Min shear = -1266 lbs D + S (2.4-3) <br /> Max moment = 1991 ft-lbs D + S (2.4-3) <br /> Min moment = -0 ft-lbs D + S (2.4-3) <br /> ->Beam properties (2D xy axis) : <br /> Span = 6.29 ft <br /> Area = 21.75 sq.in <br /> Sx = 26.28 sq.in <br /> Ixx = 95.27 sq.in <br /> ->Check shear : <br /> fv = 1.5 x V / Area = 1266 / 21.75 = 87.32 psi <br /> Fry = 180.00 x 1.15 x 1.00 x 1.00 x 1.00 = 207.00 psi <br /> Fv = 180 psi, CD = 1.15, Cm = 1.00, Ct = 1.00, Ci = 1.00. <br /> ->Check bending : <br /> fb-top = M x 12 / Sx = 23893 / 26.28 = 909.11 psi <br /> fb-btm = M x 12 / Sx = 0 / 26.28 = 0.00 psi <br /> CUSTOM DESIGN & ENGINEERING, INC. <br /> March 3, 2022 Page 44 / 67 <br /> Copyright©2022 Custom Design&Engineering,Inc.All rights reserved. <br />