200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SRUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, Washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 1 - 42" leg Page 2 8 Number 5 Bars Results shown are for 42.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.OD Service Deft. = N.A. in. Mu = 71.71 in-k Ultimate Defl.- N.A. in. Phi * Mn = 903.31 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.04 in. Mu = 49.66 in-k Ultimate Defl.= 0.28 in. Phi * Mn = 1,036.94 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 198.05 ink Ultimate Defl.= N.A. in. Phi * Mn = 955.26 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.OL (M=.5*P*e + P*Delta.) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = 0.11 in. Mu - 146.99 in-k Ultimate Defl.= 0.82 in. Phi * Mn = 1,068.99 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Deft. = 1.01 in. Mu = 539.56 in-k Ultimate Deft.= 2.99 in. Phi * Mn = 1,068.99 in-k ... CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.04 in. Mu = 794.98 in-k Ultimate Defl.= 4.53 in. Phi * Mn = 1,031.16 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.82 in. Mu = 1,024.62 in-k Ultimate Defl.= 5.80 in. Phi * Mn = 1,040.06 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.OD + 0.6W Service Defl. = 1.28 in. Mu - 738.69 in-k Ultimate Defl.= 4.26 in. Phi * Mn = 1,013.88 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.29 in. Mu 998.11 in-k Ultimate Defl.= 5.68 in. Phi * Mn = 1,033.17 in-k CASE 8 U = 0.9D + 1.OW Service load = 0.6D + 0.6W Service Defl. = 1.16 in. Mu = 678.48 in-k Ultimate Defl.= 4.01 in. Phi * Mn - 979.13 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 2.07 in. Mu = 839.60 in-k Ultimate Defl.= 5.04 in. Phi * Mn = 959.67 in-k