200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

() `-\Cl2 SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 ....... (425) 450-4075 Sheet No.: Description: Panel 7 - 39" leg Page 2 6 Number 6 Bars Results shown are for 39.00 inch wide section. CASE 1 @ Roof, U = 1.40 ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 24.28 in-k Ultimate Defl.- N.A. in. Phi * Mn = 652.73 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.03 in. Mu - 16.82 in-k Ultimate Defl.= 0.21 in. Phi * Mn = 698.03 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 67.03 in-k Ultimate Defl.- N.A. in. Phi * Mn = 666.82 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = 0.08 in. Mu = 48.98 in-k Ultimate Defl.= 0.59 in. Phi * Mn = 705.48 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R } + 0.5W Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.23 in. Mu = 284.95 in-k Ultimate Defl.= 3.46 in. Phi * Mn = 705.48 in-k CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.24 in. Mu - 462.70 in-k Ultimate Defl.= 5.67 in. Phi * Mn = 695.18 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.62 in. Mu = 480.97 in-k Ultimate Defl.= 5.87 in. Phi * Mn = 698.67 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.0D + 0.6W Service Defl. = 1.65 in. Mu - 438.76 in-k Ultimate Defl.= 5.40 in. Phi * Mn = 690.48 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.16 in. Mu - 470.80 in-k Ultimate Defl.= 5.76 in. Phi * Mn = 696.79 in-k = 1 CASE 8 U = 0.90 + 1.0W Service load = 0.6D + 0.6W Service Defl. = 1.51 in. Mu = 404.34 in-k Ultimate Defl.= 5.03 in. Phi * Mn = 679.11 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.90 in. Mu = 396.32 in-k Ultimate Defl.= ==4.96 in. Phi * Mn== = 672.75 in-k