200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT 7 Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No. : Description: Panel 7 - 60" leg Page 2 7 Number 6 Bars Results shown are for 60.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 33.26 in-k Ultimate Deft.- N.A. in. Phi * Mn = 782.98 in-k CASE 1 @ Mid-ht., U 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.OD Service Defl. = 0.03 in. Mu = 23.39 in-k Ultimate Defl.= 0.22 in. Phi * Mn = 848.71 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 91.82 in-k Ultimate Defl.= N.A. in. Phi * Mn = 803.42 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load 13 1.0D + 1.0(Lr or S or R) Service Defl. = 0.07 in. Mu = 68.25 in-k Ultimate Defl.= 0.63 in. Phi * Mn = 859.54 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.OD + 0.75L + 0.75*0,6W + 0.75(Lr or S or R) Service Defl. = 1.15 in. Mu = 397.03 in-k Ultimate Defl.= 3.65 in. Phi * Mn - 859.54 in-k CASE 4 U = 1.2D + 1.0W + 1.OL + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.16 in. Mu - 642.96 in-k Ultimate Defl.= 5.98 in. Phi * Mn = 844.57 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.25 Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.58 in. Mu = 668.93 in-k Ultimate Defl.= 6.20 in. Phi * Mn = 849.64 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.0D + 0.6W Service Defl. = 1.62 in. Mu = 608.95 in-k Ultimate Defl.= 5.70 in. Phi * Mn = 837.75 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.17 in. Mu = 654.48 in-k Ultimate Defl.= 6.08 in. Phi * Mn - 846.92 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Defl. = 1.47 in. Mu = 559.44 in-k Ultimate Defl.= 5.31 in. Phi * Mn = 821.24 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.90 in. Mu = 547.38 in-k Ultimate Defl.= 5.23 in. Phi * Mn = 812.02 in-k 4