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SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial <br /> Structural Engineers Job No. : 20-33 <br /> 12503 Bel-Red Road, Suite 100 Engr: : CT <br /> Bellevue, washington 98005 Date: 10-20-2020 <br /> (425) 450-4075 Sheet No.: <br /> Description: Panel 7 - 62" leg Page 2 <br /> 3 Number 6 Bars <br /> Results shown are for 62.00 inch wide section. <br /> CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) <br /> Service Load = 1.DD <br /> Service Defl. = N.A. in. Mu = 17.93 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 352.60 in-k <br /> CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. <br /> Service Load = 1.0D <br /> Service Deft. = 0.01 in. Mu = 12.55 in-k <br /> Ultimate Defl.- 0.21 in. Phi * Mn - 391.76 in-k <br /> CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) <br /> Service Load = 1.0D + 1.0(Lr or S or R) <br /> Service Defl. = N.A. in. Mu = 49.50 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 364.74 in-k <br /> CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) <br /> Service Load = 1.OD + 1.0(Lr or S or R) <br /> Service Deft. = 0.04 in. Mu = 36.48 in-k <br /> Ultimate Defl.= 0.61 in. Phi * Mn = 398.25 in-k <br /> ___ <br /> CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W <br /> Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.26 in. Mu = 212.21 in-k <br /> Ultimate Defl.= 3.55 in. Phi * Mn = 398.25 in-k <br /> CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) <br /> Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.26 in. Mu = 345.28 in-k <br /> Ultimate Defl.-- 5.90 in. Phi * Mn = 389.29 in-k <br /> CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.OL + 0.2S <br /> Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) <br /> Service Deft. = 0.31 in. Mu 358.72 in-k <br /> Ultimate Defl.= 6.09 in. Phi * Mn = 392.32 in-k <br /> CASE 6 U = 1.2D + 1.0w <br /> Service load = 1.OD + 0.6W <br /> Service Defl. = 0.32 in. Mu - 327.54 in-k <br /> Ultimate Defl.= 5.65 in. Phi * Mn = 385.21 in-k <br /> CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E <br /> Service load = (1 + 0.14Sds)D + 0.7E <br /> Service Defl. = 1.02 in. Mu - 351.24 in-k <br /> Ultimate Defl.= 5.98 in. Phi * Mn = 390.69 in-k <br /> CASE 8 U = 0.9D + 1.0W <br /> Service load = 0.6D + 0.6W <br /> Service Defi. = 0.31 in. Mu = 301.71 in-k <br /> Ultimate Defl.= 5.32 in. Phi * Mn = 375.36 in-k <br /> k <br /> CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E _.. <br /> Service load = (0.6 - 0.14 Sds)D + 0.7E <br /> Service Defl. = 0.81 in. Mu = 295.45 in-k <br /> Ultimate Defl.= 5.28 in. Phi * Mn = 369.86 in-k <br />