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SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial <br /> Structural Engineers Job No. : 20-33 <br /> 12503 Bel-Red Road, Suite 100 Engr: : CT <br /> Bellevue, Washington 98005 Date: : 10-20-2020 <br /> '..... (425) 450-4075 Sheet No. : <br /> II <br /> Description: Panel 10 - 60" leg Page 2 <br /> 8 Number 5 Bars <br /> Results shown are for 60.00 inch wide section. <br /> CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) <br /> Service Load = 1,0D <br /> Service Defl. = N.A. in. Mu = 16.90 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 646.60 in-k <br /> CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) <br /> Service Load = 1.0D <br /> Service Defl. = 0.01 in, Mu = 12.01 in-k <br /> Ultimate Defl.= 0.11 in. Phi * Mn = 706.44 in-k <br /> CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) <br /> Service Load = 1.OD + 1.0(Lr or S or R) <br /> Service Defi. = N.A. in. Mu - 46.69 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn - 684.79 in-k <br /> { <br /> CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) <br /> Service Load = 1.08 + 1.0(Lr or S or R) <br /> Service Defi. = 0.03 in. Mu = 38.46 in-k <br /> Ultimate Defl.= 0.35 in. Phi * Mn = 735.68 in-k <br /> CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W <br /> ., Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.97 in. Mu = 393.68 in-k <br /> Ultimate Defl.= 3.57 in. Phi * Mn = 735.68 in-k <br /> CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) <br /> Service load = 1.0D + 0.751 + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 1.01 in. Mu = 634.55 in-k <br /> Ultimate Defl.= 5.92 in. Phi * Mn = 707.66 in-k (' <br /> a �F' <br /> CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S <br /> Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) <br /> Service Defl. = 1.45 in. Mu = 652.95 in-k <br /> Ultimate Defl.= 6.08 in. Phi * Mn = 709.65 in-k <br /> CASE 6 U = 1.2D + 1.0W �. <br /> Service load = 1.0D + 0.6W <br /> Service Defl. = 1.53 in. Mu = 590.89 in-k <br /> Ultimate Defl.- 5.59 in. Phi * Mn = 694.87 in-k <br /> CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E <br /> Service load = (1 + 0.14Sds)D + 0.7E <br /> Service Defi. = 2.09 in. Mu = 634.46 in-k <br /> Ultimate Defl.= 5.94 in. Phi * Mn - 704.54 in-k <br /> CASE 8 U = 0.9D + 1.0W <br /> Service load = 0.6D + 0.6W <br /> Service Defl. = 1.41 in. Mu = 543.89 in-k <br /> Ultimate Defl.= 5.24 in. Phi * Mn = 677.45 in-k <br /> CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E <br /> Service load = (0.6 - 0.14 Sds)D + 0.7E <br /> Service Defl. = 1.87 in. Mu = 532.76 in-k <br /> Ultimate Defl.- 5.19 in. Phi * Mn = 667.72 in-k <br />