200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 10 - 37" leg Page 2 4 Number 5 Bars Results shown are for 37.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e --- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu - 9.15 in-k Ultimate Defl.= N.A. in. Phi * Mn - 328.12 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.01 in. Mu = 6.54 in-k Ultimate Defl.= 0.11 in. Phi * Mn = 361.38 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 25.28 in-k Ultimate Defl. N.A. in. Phi * Mn = 349.34 in-k e CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) `. Service Load = 1.OD + 1.0(Lr or S or R) Service Deft. = 0.03 in. Mu = 20.94 in-k Ultimate Defl.= 0.35 in. Phi * Mn = 377.66 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W - Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.79 in. Mu = 214.39 in-k Ultimate Defl.= 3.62 in. Phi * Mn = 377.66 in-k CASE 4 U = 1.2D + 1.OW + 1.0L + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.83 in. Mu = 345.54 in-k Ultimate Defl.= 6.03 in. Phi * Mn = 362.06 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.OL + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.30 in. Mu = 355.81 in-k Ultimate Defl.= 6.20 in. Phi * Mn = 363.17 in-k CASE 6 U = 1.2D + 1.OW Service load = 1.OD + 0.6W Service Defl. = 1.41 in. Mu = 321.66 in-k Ultimate Defl.= 5.70 in. Phi * Mn = 354.94 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.00 in. Mu = 345.48 in-k Ultimate Defl.= 6.05 in. Phi * Mn = 360.32 in-k j CASE 8 U = 0.9D + 1.OW Service load = 0.6D + 0.6W Service Defl. = 1.29 in. Mu = 295.82 in-k r Ultimate Defl.= 5.36 in. Phi * Mn = 345.26 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E 1 Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.79 in. Mu - 289.59 in-k [. Ultimate Defl.= 5.32 in. Phi * Mn = 339.85 in-k