200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT / Bellevue, washington 98005 Date: 10 20 2D20 t...... (425) 450-4075 Sheet No.: Description: Panel 10 - 30" leg Page 2 ______ 4 Number 5 Bars Results shown are for 30.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 8.45 in-k Ultimate Defl.= N.A. in. Phi * Mn = 323.30 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.OD Service Defl. = 0.01 in. Mu = 6.01 in-k Ultimate Deft.= 0.11 in. Phi * Mn = 353.22 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defi. = N.A. in. Mu; = 23.35 in-k Ultimate Deft.= N.A. in. Phi * Mn = 342.39 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = 0.03 in. Mu = 19.23 in-k Ultimate Defl.= 0.35 in. Phi * Mn = 367.84 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.97 in. Mu = 196.84 in-k Ultimate Defl.= 3.57 in. Phi * Mn = 367.84 in-k CASE 4 U = 1.2D + 1.OW + 1.0L + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.01 in. Mu = 317.27 in-k i. Ultimate Defl.= 5.92 in. Phi * Mn = 353.83 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defi. = 1.45 in. Mu = 326.48 in-k Ultimate Deft.= 6.08 in. Phi * Mn = 354.83 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.OD + 0.6W Service Defl. = 1.53 in. Mu = 295.44 in-k Ultimate Defl.= 5.59 in. Phi * Mn = 347.43 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defi. = 2.09 in. Mu = 317.23 in-k Ultimate Defl.= 5.94 in. Phi * Mn = 352.27 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Defl. = 1.41 in. Mu = 271.95 in-k Ultimate Defl.= 5.24 in. Phi * Mn = 338.73 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.87 in. Mu = 266.38 in-k Ultimate Defl.- 5.19 in. Phi * Mn = 333.86 in-k