200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT �..'.. Bellevue, washington 98005 Date: : 10-20-2020 ..,.... (425) 450-4075 Sheet No.: Description: Panel 11 - 94" leg Page 2 7 Number 5 Bars Results shown are for 94.00 inch wide section. CASE 1 @ Roof, U = 1.40 ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 16.90 in-k Ultimate Deft.= N.A. in. Phi * Mn = 584.58 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.01 in. Mu = 11.93 in-k Ultimate Defl.= 0.11 in. Phi * Mn - 648.17 in-k ii CASE 2 @ Roof, U = I.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 46.69 in-k Ultimate Deft.= N.A. in. Phi * Mn = 625.12 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.OL (M=.5*P*e + P*Delta.) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = 0.02 in. Mu = 37.76 in-k Ultimate Defl.= 0.33 in. Phi * Mn = 679.37 in-k __ ".. CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W =_ Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defi. = 0,26 in. Mu = 386.52 in-k • Ultimate Defl.= 3.41 in. Phi * Mn = 679.37 in-k CASE 4 U = 1.2D + 1.OW + 1.OL + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.26 in. Mu = 629.64 in-k Ultimate Defl.= 5.76 in. Phi * Mn = 649.47 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.OL + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defi. = 0.57 in. Mu = 647.56 in-k Ultimate Deft,= 5.91 in. Phi * Mn = 651.59 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.0D + 0.6W Service Defl. = 0.75 in. Mu = 588.09 in-k Ultimate Defl.= 5.48 in. Phi * Mn = 635.85 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defi. = 1.42 in. Mu = 630.06 in-k Ultimate Defl.= 5.79 in. Phi * Mn = 646.15 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Defl. = 0.67 in. Mu = 542.90 in-k Ultimate Defl.= 5.19 in. Phi * Mn = 617.33 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.25 in. Mu - 532.36 in-k Ultimate Defl.= 5.17 in. Phi * Mn = 606.99 in-k