200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial . Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 11 - 64" leg Page 2 4 Number 5 Bars Results shown are for 64.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 8.45 in-k Ultimate Defl.= N.A. in. Phi * Mn = 334.25 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.01 in. Mu = 5.65 in-k Ultimate Defl.- 0.09 in. Phi * Mn = 366.46 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu 23.35 in-k Ultimate Defl.= N.A. in. Phi * Mn - 354.78 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.01 in. Mu - 17.44 in-k Ultimate Defl.= 0.27 in. Phi * Mn = 382.29 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W i. ........' Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.19 in. Mu = 178.55 in-k Ultimate Defl.= 2.72 in. Phi * Mn = 382.29 in-k CASE 4 U = 1.2D + 1.0W + 1.OL + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.19 in. Mu - 297.82 in-k Ultimate Defl.= 4.71 in. Phi * Mn = 367.12 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.25 Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) is Service Defl. = 0.22 in. Mu = 305.82 in-k Ultimate Defl.= 4.82 in. Phi * Mn = 368.20 in-k CASE 6 U = 1.2D + 1.OW (. Service load = 1.0D + 0.6W Service Defl. = 0.24 in. Mu = 280.75 in-k f. Ultimate Defl.= 4.51 in. Phi * Mn = 360.21 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 0.34 in. Mu = 298.73 in-k Ultimate Defl.= 4.74 in. Phi * Mn - 365.43 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6➢ + 0.6W Service Defl. = 0.23 in. Mu = 262.55 in-k Ultimate Defl.= 4.32 in. Phi * Mn = 350.83 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 0.28 in. Mu = 259.15 in-k Ultimate Defl.= 4.32 in. Phi * Mn = 345.59 in-k gt