200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

tAr (PA SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 gel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No. : Description: Panel 33 - 32" leg Page 2 5 Number 5 Bars Results shown are for 32.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 28.40 in-k Ultimate Defl.=. N.A. in. Phi * Mn = 564.22 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1,0D Service Defl. = 0.02 in. Mu = 18.34 in-k Ultimate Defl.= 0.16 in. Phi * Mn = 642.88 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1,OL (M=P*e, No P*Delta) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu - 78.43 in-k Ultimate Defl.= N.A. in. Phi * Mn = 585.38 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.05 in. Mu - 52.11 in-k Ultimate Defl.= 0.44 in. Phi * Mn = 652.59 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W i. Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.47 in. Mu = 247.12 in-k Ultimate Defl.= 2.08 in. Phi * Mn = 652.59 in-k CASE 4 U = 1,2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.48 in. Mu = 398.98 in-k Ultimate Defl.= 3.43 in. Phi * Mn = 637.09 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.OL + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.12 in. Mu = 519.01 in-k Ultimate Defl.= 4.42 in. Phi * Mn = 643.60 in-k CASE 6 U = 1.2D + 1.OW Service load = 1.OD + 0.6W Service Defl. = 0.75 in. Mu = 380.49 in-k Ultimate Defl.= 3.30 in. Phi * Mn = 630.03 in-k CASE 7 U = (1,2 -1- 0.2 Sds)D + 1.0E Service load = (1 + 0,14Sds)D + 0,7E 1 Service Defl. = 1.58 in. Mu = 510.25 in-k Ultimate Defl.= 4.36 in. Phi * Mn = 640.76 in-k CASE 8 U = 0.9D + 1.OW Service load = 0.6D + 0.6W Service Defl. = 0.68 in. Mu = 356.57 in-k 4 Ultimate Defl.- 3.17 in. Phi * Mn = 610.68 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.46 in. Mu = 446.83 in-k Ultimate Defl.= 4.03 in. Phi * Mn - 599.86 in-k