200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

fig " \ SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 33 - 42" leg Page 2 =_5 Number 5 Bars Results shown are for 42.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.OD Service Defl. = N.A. in. Mu = 31.37 in-k Ultimate Defl.= N.A. in. Phi * Mn = 572,50 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.02 in. Mu = 20.41 in-k Ultimate Defl.- 0.16 in. Phi * Mn = 661.80 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 86.65 in-k Ultimate Defl.- N.A. in. Phi * Mn = 596.50 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.04 in. Mu - 57.98 in-k Ultimate Defl.= 0.45 in. Phi * Mn = 672.84 in-k = CASE 3 U = 1.2D + 1.6 ( Lr or Sor R ) + 0.5W Service load = 1.OD + 0.75E + 0.75*0.6W + 0.75(Lr or S or R) =... Service Defl. = 0.26 in. Mu = 274.97 in-k Ultimate Defl.= 2.14 in. Phi * Mn = 672.84 in-k 1- CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.26 in. Mu = 443.78 in-k E..; Ultimate Defl.= 3.54 in. Phi * Mn = 655.22 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 0.96 in. Mu = 577.42 in-k Ultimate Defl.= 4.56 in. Phi * Mn = 662.61 in-k =_CASE 6 U = 1.2D + 1.OW _ Service load = 1.OD + 0.6W F.... Service Defl. = 0.55 in. Mu = 423.12 in-k Ultimate Defl.= 3.41 in. Phi * Mn = 647.19 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 1.48 in. Mu = 567.67 in-k Ultimate Defl.= 4.50 in. Phi * Mn 659.41 in-k CASE 8 U = 0.9D + 1.OW Service load = 0.6D + 0.6W Service Defl, = 0.48 in. Mu = 396.13 in-k Ultimate Defl.= 3.28 in. Phi * Mn = 625.21 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = I.36 in. Mu - 496.03 in-k Ultimate Defl.= 4.18 in. Phi * Mn = 612.93 in-k