200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: 10-21 2024 ..._; (425) 450-4075 Sheet No. : Description: Panel 35 - 42" leg (w/ girder axial) Page 2 6 Number 6 Bars Results shown are for 42.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.OD Service Defl. = N.A. in. Mu = 133.74 in-k Ultimate Defl.- N.A. in. Phi * Mn = 989.36 in-k _ ___ CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.07 in. Mu = 95.50 in-k Ultimate Defl.- 0.50 in. Phi * Mn = 1,122.45 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 342.92 in-k Ultimate Defl.= N.A. in. Phi * Mn = 1,073.90 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.19 in. Mu = 280.79 in-k Ultimate Deft.= 1.42 in. Phi * Mn = 1,186.50 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Deft. = 1.17 in. Mu = 705.61 in-k Ultimate Defl.= 3.57 in. Phi * Mn = 1,186.50 in-k CASE 4 U = 1.20 + 1.0W + 1.OL + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.23 in. Mu = 877.29 in-k Ultimate Defl.= 4.61 in. Phi * Mn = 1,124.44 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.97 in. Mu = 1,097.77 in-k Ultimate Defl.= 5.75 in. Phi * Mn = 1,129.47 in-k CASE 6 U = 1.2D + 1.OW Service load = 1.0D + 0.6W Service Defl. = 1.30 in. Mu = 780.20 in-k Ultimate Defl.= 4.17 in. Phi * Mn = 1,096.00 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.23 in. Mu = 1,052.50 in-k Ultimate Defl.= 5.55 in. Phi * Mn = 1,118.12 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Defl. = 1.13 in. Mu = 703.46 in-k Ultimate Defl.= 3.86 in. Phi * Mn = 1,056.08 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.93 in. Mu = 855.76 in-k Ultimate Detl.= 4.77 in. Phi * Mn = 1,033.71 in-k = I: