200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No. : Description: Panel 40 - 24" leg Page 2 5 Number 5 Bars Results shown are for 24.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defi. = N.A. in. Mu = 17.52 in-k Ultimate Defl.= N.A. in. Phi * Mn = 382.91 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.OD Service Defl. = 0.04 in. Mu = 12.05 in-k Ultimate Defl.= 0.28 in. Phi * Mn = 405.06 in-k = == CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defi. = N.A. in. Mu = 48.38 in-k Ultimate Defl.= N.A. in. Phi * Mn = 393.21 in-k CASE 2 @ Mid-ht, U = 1.2D + 1,6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = 0.11 in. Mu = 36.60 in-k Ultimate Defl.= 0.84 in. Phi * Mn = 412.09 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.25 in. Mu = 170.27 in-k Ultimate Defl.= 3.90 in. Phi * Mn 412.09 in-k CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.26 in. Mu - 258.94 in-k Ultimate Defl.= 6.01 in. Phi * Mn = 404.54 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.OL + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.67 in. Mu - 266.28 in-k Ultimate Defl.= 6.17 in. Phi * Mn = 405.79 in-k -_CASE 6 U = 1.2D + 1.OW Service load = 1.0D + 0.6W Service Defl. = 1.64 in. Mu = 241,11 in-k Ultimate Defl.- 5.62 in. Phi * Mn - 401.09 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.17 in. Mu = 258.76 in-k Ultimate Deft.= 6.00 in. Phi * Mn = 404.41 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Defl. = 1.48 in. Mu = 222.00 in-k Ultimate Defl.= 5.23 in. Phi * Mn = 395.11 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.88 in. Mu = 217.44 in-k Ultimate Defl.= ===-5.15 in. == Phi * Mn = 391.77 in-k }