200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-21-2020 (425) 450-4075 Sheet No.: Description: Panel 44 - 42" leg Page 2 =-I 7 Number 6 Bars Results shown are for 42.00 inch wide section. _______ _ = CASE 1 @ Roof, U = 1.4D ( M = P*e --- No P * Deflection. ) Service Load = 1.OD Service Defl. = N.A. in. Mu = 29.09 in-k Ultimate Defl.= N.A. in. Phi * Mn = 754.95 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.04 in. Mu = 19.77 in-k Ultimate Defl.= 0.23 in. Phi * Mn = 797.83 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 80.33 in-k Ultimate Defl.- N.A. in. Phi * Mn = 771.50 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) { Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = 0.10 in. Mu - 58.60 in-k Ultimate Defl.= 0.68 in. Phi * Mn 808.05 in-k r." CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.26 in. Mu - 308.66 in-k Ultimate Defl.= 3.56 in. Phi * Mn = 808.05 in-k = I CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) j Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 1.27 in. Mu = 488.68 in-k Ultimate Defl.= 5.68 in. Phi * Mn = 795.95 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) { i' Service Defl. = 1.65 in. Mu = 504.86 in-k Ultimate Defl.= 5.86 in. Phi * Mn = 798.82 in-k _ _ ! CASE 6 U = 1.2D + 1.0W Service load = 1.OD + 0.6W Service Defl. = 1.65 in. Mu = 460.26 in-k Ultimate Defl.= 5.38 in. - Phi * Mn = 790.42 in-k _ _ _ ___ __ # CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.l4Sds)D + 0.7E [ !' I ] Service Defl. = 2.15 in. Mu = 492.84 in-k Ultimate Defl.= 5.73 in. Phi * Mn = 796.61 in-k CASE 8 U = 0.9D + 1.0W I {' Service load = 0.6D + 0.6W Service Defl. = 1.51 in. Mu = 425.57 in-k Ultimate Defl.= 5.01 in. Phi * Mn = 779.27 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.90 in. Mu = 417.82 in-k Ultimate Def1.= 4.95 in. Phi * Mn = 773.03 in-k