200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 ... . (425) 450-4075 Sheet No.: Description: Panel 73 - 42" leg Page 2 6 Number 5 Bars Results shown are for 42.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 11.46 in-k Ultimate Defl.= N.A. in. Phi * Mn = 481.20 in-k CASE 1 @ Mid-ht., U = 1.4➢ ( M = .5*P*e + P * Deflection. ) Service Load = 1.OD Service Defl. = 0.01 in. Mu = 7.93 in-k Ultimate Defl.= 0.10 in. Phi * Mn = 521.44 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defi. = N.A. in. Mu = 31.68 in-k Ultimate Defl.= N.A. in. Phi * Mn = 506.88 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.03 in. Mu = 25.03 in-k Ultimate Defl.= 0.31 in. Phi. * Mn = 541.11 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.OD + 0.75E + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.86 in. Mu - 256.27 ink Ultimate Defl.= 3.20 in. Phi * Mn 541.11 in-k CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.0D + 0.75E + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.89 in. Mu = 418.47 in-k Ultimate Defl.= 5.36 in. Phi * Mn = 522.26 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.OL + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75E + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.29 in. Mu = 430.27 in-k Ultimate Defl.= 5.50 in. Phi * Mn = 523.60 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.0D + 0.6W Service Defl. = 1.37 in. Mu = 391.60 in-k i. Ultimate Defl.= 5.08 in. Phi * Mn = 513.66 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defi. = 1.87 in. Mu = 418.92 in-k Ultimate Defl.= 5.38 in. Phi * Mn = 520.16 in-k CASE 8 U = 0.9D + 1.OW Service load = 0.6D + 0.6W Service Defl. 1.27 in. Mu = 362.78 in-k F` Ultimate Defl.= 4.79 in. Phi * Mn = 501.95 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.68 in. Mu = 356.54 in-k Ultimate Defl.= 4.75 in. Phi * Mn = 495.40 in-k