200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: t Description: Panel 73 - 60" leg Page 2 7 Number 5 Bars Results shown are for 60.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 15.29 in-k Ultimate Defl.= N.A. in. Phi * Mn = 570.95 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.OD Service Dell. = 0.01 in. Mu - 10.84 in-k Ultimate Defl.= 0.11 in. Phi * Mn = 626.06 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.OD + 1.0(Lr or S or R) Service Dell. = N.A. in. Mu = 42.26 in-k Ultimate Defl.= N.A. in. Phi * Mn = 606.11 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) ;. Service Load = 1.OD + 1.0(Lr or S or R) Service Dell. = 0.03 in. Mu - 34.57 in-k Ultimate Defl.= 0.34 in. Phi * Mn - 653.02 in-k ':. CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Dell. = 0.82 in. Mu - 353.93 in-k Ultimate Defl.= 3.51 in. Phi * Mn = 653.02 in-k CASE 4 U = 1.2D + 1.OW + 1.OL + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) ?f Service Dell. = 0.85 in. Mu = 572.31 in-k Ultimate Defl.= 5.85 in. Phi * Mn = 627.19 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0,525E + 0.75(Lr or S or R) Service Dell. = 1.31 in, Mu = 588.81 in-k Ultimate Defl.= 6.00 in. Phi * Mn - 629.02 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.0D + 0.6W Service Dell. = 1.40 in. Mu = 533.48 in-k Ultimate Defl.= 5.53 in. Phi * Mn - 615.39 in-k = l CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + O.l4Sds)D + 0.7E Service Dell. = 1.97 in. Mu = 572.39 in-k Ultimate Defl.= 5.87 in. Phi * Mn = 624.31 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Dell. = 1.29 in. Mu = 491.58 in-k Ultimate Defl.= 5.21 in. Phi * Mn = 599.35 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1,0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Dell. = 1.77 in. Mu - 481.73 in-k Ultimate Defl.= 5.16 in. Phi * Mn - 590.39 in-k