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SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial <br /> Structural Engineers Job No. : 20-33 <br /> 12503 Bel-Red Road, Suite 100 Engr: : CT <br /> Bellevue, washington 98005 Date: 10-20-2020 <br /> (425) 450-4075 Sheet No.: <br /> Description: Panel 77 - 42" leg Page 2 <br /> 7 Number 5 Bars <br /> Results shown are for 42.00 inch wide section. <br /> CASE 1 @ Roof, U = 1.4D ( M = P*e - No P * Deflection. ) <br /> Service Load = 1.OD <br /> Service Defl. = N.A. in. Mu = 69.71 in-k <br /> Ultimate Deft.- N.A. in. Phi * Mn - 799.75 in-k <br /> CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) <br /> Service Load = 1.0D <br /> Service Defl. = 0.03 in. Mu = 47.41 in-k <br /> Ultimate Defl.= 0.23 in. Phi * Mn = 952.37 in-k <br /> CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) <br /> Service Load = 1.0D + l.0(Lr or S or R) <br /> Service Defl. = N.A. in. Mu = 192.65 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 851.17 ink <br /> CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.OL (M=.5*P*e + P*Delta.) <br /> Service Load = 1.0D + 1.0(Lr or S or R) <br /> Service Defl. = 0.08 in. Mu = 137.70 in-k <br /> Ultimate Defl.= 0.66 in. Phi * Mn = 981.13 in-k <br /> CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W <br /> f . Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.64 in. Mu - 450.61 in-k <br /> Ultimate Defl.= 2.17 in. Phi * Mn = 981.13 in-k <br /> CASE 4 U = 1.2D + 1.0W + 1.OL + 0.5 (Lr or S or R) <br /> Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.66 in. Mu - 654.64 in-k <br /> Ultimate Defl.= 3.25 in. Phi * Mn = 943.77 in-k <br /> CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S <br /> Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) <br /> Service Defl. = 1.22 in. Mu = 839.74 in-k <br /> Ultimate Defl.= 4.13 in. Phi * Mn = 954.98 in-k <br /> CASE 6 U = 1.2D + 1.0W <br /> Service load = 1.0D + 0.6W <br /> Service Defl. = 0.82 in. Mu = 608.79 in-k <br /> Ultimate Defl.= 3.06 in. Phi * Mn = 926.71 in-k <br /> CASE 7 U - (1.2 + 0.2 Sds)D + 1.0E • <br /> Service load = (1 + 0.14Sds)D + 0.7E <br /> Service Defl. = 1.55 in. Mu = 818.76 in-k <br /> Ultimate Defl.= 4.05 in. Phi * Mn = 948.17 in-k <br /> CASE 8 U = 0.9D + 1.0W <br /> Service load = 0,6D + 0.6W <br /> Service Defl. = 0.73 in, Mu = 560.90 in-k <br /> Ultimate Defl.- 2.91 in. Phi * Mn = 888.00 in-k <br /> CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E <br /> Service load = (0.6 - 0.14 Sds)D + 0.7E <br /> Service Defl. = 1.41 in. Mu = 693.92 in-k <br /> Ultimate Defl.= 3.67 in. Phi * Mn = 866.33 in-k <br />