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SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial <br /> Structural Engineers Job No. : 20-33 <br /> 12503 Bel-Red Road, Suite 100 Engr: : CT <br /> Bellevue, washington 98005 Date: 10-20-2020 <br /> (425) 450-4075 Sheet No.: <br /> Description: Panel 78 - 42" leg Page 2 <br /> 6 Number 5 Bars <br /> Results shown are for 42.00 inch wide section. <br /> CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) <br /> Service Load = 1.0D <br /> Service Defl. = N.A. in. Mu = 56.60 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 689.71 in-k <br /> CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) <br /> Service Load = 1.0D <br /> Service Defl. = 0.03 in. Mu = 39.03 in-k <br /> Ultimate Defl.= 0.23 in. Phi * Mn = 823.87 in-k <br /> =CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, NoP*Delta)�S6 <br /> Service Load = 1.0D + 1.0(Lr or S or R) <br /> Service Defl, = N.A. in. Mu = 156.32 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 732.18 in-k <br /> CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) <br /> Service Load = 1,O0 + 1.0(Lr or S or R) <br /> Service Defl. = 0.07 in. Mu = 112.97 in-k <br /> Ultimate Defl.= 0.66 in, Phi * Mn = 846.58 in-k <br /> CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W <br /> Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.67 in. Mu = 421.74 in-k <br /> Ultimate Defl.= 2.47 in. Phi * Mn = 846.58 in-k <br /> CASE 4 U = 1.2D + 1.OW + 1.0L + 0.5 (Lr or S or R) <br /> Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.69 in. Mu = 635.15 in-k <br /> Ultimate Defl.= 3.83 in. Phi * Mn = 815.61 in-k <br /> CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0E + 0.2S <br /> Service load = (1,0 t 0.1 Sds)D + 0.75E + 0.525E + 0.75(Lr or S or R) <br /> Service Defl. = 1.39 in. Mu = 821.03 in-k <br /> Ultimate Defl.= 4.91 in. Phi * Mn = 825.84 in-k <br /> CASE 6 U = 1.2D + 1.0W <br /> Service load = 1.0D + 0.6W • <br /> Service Defl, = 0.93 in. Mu = 594.87 in-k <br /> Ultimate Defl.= 3.64 in. Phi * Mn = 801.48 in-k <br /> CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E <br /> Service load = (1 + 0.14Sds)D + 0.7E <br /> Service Defl. = 1.83 in. Mu = 802.36 in-k <br /> Ultimate Defl.= 4.82 in. Phi * Mn = 820.21 in-k <br /> CASE 8 U - 0.9D + 1.0W <br /> Service load = 0.6D + 0.6W <br /> Service Defl. = 0.83 in. Mu = 547.87 in-k <br /> (:. Ultimate Defl.= 3.47 in. Phi * Mn = 767.75 in-k <br /> CASE 9 U = (0.9 - 0.2 Sds)D -I- 1.0E <br /> Service load = (0.6 - 0.14 Sds)D + 0.7E <br /> Service Defl. = 1.68 in. Mu = 678.74 in-k <br /> Ultimate Defl.= 4.38 in. Phi * Mn = 748.88 in-k <br />