200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

-V r ' SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 90 - 36" leg Page 2 5 Number 5 Bars Results shown are for 36.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.OD Service Defl. = N.A. in. Mu = 10.33 in-k Ultimate Deft.- N.A. in. Phi * Mn = 559.72 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = l,OD Service Defl. = 0.01 in. Mu 6.72 in-k Ultimate Defl.= 0.05 in. Phi * Mn = 667.54 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M-P*e, No P*Delta) Service Load = 1.OD + l.0(Lr or S or R) Service Defl. = N.A. in. Mu = 28.52 in-k Ultimate Defl.= N.A. in. Phi * Mn = 567.53 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.02 in. Mu = 18.23 in-k Ultimate Defl.= 0.13 in. Phi * Mn = 659.95 in-k { CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.30 in. Mu - 229.75 in-k Ultimate Defl.= 1.66 in. Phi * Mn - 659.95 in-k CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.30 in. Mu = 426.91 in-k Ultimate Defl.- 3.10 in. Phi * Mn = 654.24 in-k =_CASE 5 U = (1.2 + 0.2 Sds)D + 1,0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 0.91 in. Mu = 569.21 in-k Ultimate Defl.= 4.08 in, Phi * Mn = 665.97 in-k = CASE 6 U = 1.2D + 1.0W o- Service load = LOU + 0.6W Service Defl. = 0.65 in. Mu = 420.48 in-k Ultimate Defi,- 3.07 in. Phi * Mn = 651.64 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load - (1 + 0.14Sds)D + 0.7E Service Defl. = 1.45 in. Mu = 566.24 in-k Ultimate Defl.= 4.06 in. Phi * Mn = 664.93 in-k CASE 8 U = 0.9D + 1.OW Service load = 0.6D + 0.6W Service Defl. = 0.61 in. Mu = 396.31 in-k Ultimate Deft.= 2.98 in. Phi * Mn = 627.71 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defi. = 1.39 in. Mu = 500.05 in-k Ultimate Defl.= 3.83 in. Phi * Mn = 614.32 in-k