200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SRUTLER CONSULTING ENGINEERS, INC. Job Name : Haywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, Washington 98005 Date: 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 90 - 46" leg Page 2 5 Number 5 Bars Results shown are for 46.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D • Service Deft. = N.A. in. Mu = 11.19 in-k Ultimate Defl.= N.A. in. Phi * Mn = 565.61 in-k CASE 1 @ Mid-ht„ U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load = 1.0D Service Defl. = 0.00 in. Mu = 7.31 in-k Ultimate Defl.- 0.05 in. Phi * Mn - 685.02 in-k CASE 2 @ Roof, U - 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) j. Service Load = 1.0D + 1.0(Lr or S or R) li Service Deft. = N.A. in. Mu = 30.90 in-k Ultimate Defl.= N.A. in. Phi * Mn = 574.25 in-k • CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.OL (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.01 in. Mu = 19.84 in-k Ultimate Defl.= 0.13 in. Phi * Mn = 676.60 in-k �' : CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.21 in. Mu = 250.01 in-k . Ultimate Defl.= 1.69 in. Phi * Mn = 676.60 in-k i. CASE 4 U = 1.2D + 1.0W + 1.OL + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.21 in. Mu = 464.54 in-k Ultimate Defl.= 3.17 in. Phi * Mn = 670.27 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) • Service Defl. = 0.74 in. Mu - 619.41 in-k Ultimate Defl.= 4.16 in. Phi * Mn = 683.28 in-k • CASE 6 U = 1.2D + 1.0W Service load = 1.OD + 0.6W • Service Defl. = 0.46 in, Mu = 457,54 in-k Ultimate Defl.= 3.13 in. Phi * Mn = 667.39 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 1.34 in, Mu = 616.17 in-k Ultimate Defl.= 4.14 in. Phi * Mn = 682.13 in-k CASE B U = 0.9D + l.OW Service load = 0.6D + 0.6W Service Defl. = 0.42 in. Mu = 431.07 in-k t • Ultimate Defl.= 3.06 in. Phi * Mn = 640.86 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.29 in. Mu = 543.83 in-k Ultimate Defl.= 3.93 in. Phi * Mn = 626.03 in-k P