200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 95 - 26" leg Page 2 5 Number 7 Bars Results shown are for 26,00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.0D Service Defl. = N.A. in. Mu = 11.14 in-k Ultimate Defl.= N.A. in. Phi * Mn = 996.00 in-k CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) Service Load - 1.OD Service Defl. = 0.01 in. Mu = 7.27 in-k Ultimate Defl.= 0.05 in. Phi * Mn = 1,094.38 in-k CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) is Service Defi. = N.A. in. Mu = 30.77 in-k Ultimate Defl.= N.A. in. Phi * Mn = 1,002.43 in-k CASE 2 @ Mid-ht, U = 1.2D + 1.6(Lx or S or R) + 1.OL (M=.5*P*e + P*Delta.) Service Load = 1.OD + 1.0(Lr or S or R) Service Defl. = 0.03 in. Mu = 19.64 in-k Ultimate Deft.= 0.13 in. Phi * Mn = 1,086.79 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W k Service load = 1.0D + 0.751 + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.92 in. Mu = 307.13 in-k Ultimate Defl.- 2.03 in. Phi * Mn = 1,086.79 in-k CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.92 in. Mu = 577.74 in-k Ultimate Defl.= 3.63 in. Phi * Mn = 1,082.15 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defl. = 1.58 in. Mu = 773.82 in-k Ultimate Defl.= 5.10 in. Phi * Mn = 1,092.88 in-k CASE 6 U = 1.2D + 1.OW= Service load = 1.OD + 0.6W Service Defl. = 1.29 in. Mu = 570.20 in-k Ultimate De£l.= 3.78 in. Phi * Mn = 1,080.04 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1,0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.18 in. Mu = 770.23 in-k Ultimate Defl.= 5.08 in. Phi * Mn = 1,092.04 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Defl. = 1,22 in. Mu = 536.11 in-k Ultimate Defl.= 3.60 in. Phi * Mn = 1,058.38 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 2,02 in. Mu = 676.48 in-k Ultimate Defl.= 4.57 in. Phi * Mn = 1,046.23 in-k