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valmont Industries, Inc. <br />Foundation Design <br />Filename :C:\impax\project\FdnData\485175FDN.lfn <br />Title :P40115A09AB <br />Engineer :IW708044 <br />Date :12/1/2021 12:00:00 AM <br />Reactions at Top of Foundation <br />M = Moment 99728 (ft-lbs) <br />Torsion 2761 (ft-lbs) <br />P = shear 3619 (lbs) <br />Axial 2598 (lbs) <br />vo .= shear overload - 1.50 <br />TO .= Torsion overload = 1.50 <br />steel Properties variables <br />As = Min. required longitudinal reinforcing steel (in2) <br />p = Min. longitudinal reinforcing steel ratio <br />----- ACI 318-99 Concrete Moment check ----- <br />Per Section 15.8.2.1 <br />steel Properties <br />p = 0.005 <br />As = 5.09 (in2) <br />----- AASHTO 1994 Concrete Moment check ----- <br />steel Properties <br />p = 0.005 <br />As = 5.09 (in2) <br />Per AASHTo 8.17.2.1.3 the maximum spacing of longitudinal bars must be <br />less thatn 12 inches in the pattern <br />----- IBc 2000 concrete Moment check ----- <br />section 1809.1.2.1 Cat 0 p = 0.0025 pg.444 <br />steel Properties <br />= 0.0025 <br />As = 2.54 (in2) <br />----- Round Section with circular core Method Concrete Moment check ----- <br />steel Properties <br />LF = 2.00 Load Factor <br />As = 4.80 (in2) <br />phiv = 0.75 <br />phiA = 0.65 <br />Assuming tension controls (eccentricity>balanced) condtion use the <br />the Whitney-Hognestad formula. <br />DpRt = Depth to Rotation (ft) <br />DpRt = 6.8586 <br />Ecc = (Depth to Rotation) + Mx / vy (ft) <br />m = 60000 / (0.85 ` fc) <br />phiA = 0.650 <br />rf ratio = Reinforcment Ratio <br />varl = ((0.85 ` Ecc / B) - 0.38)A2 <br />var2 = rf_ratio ` m (B - 8 in) / (2.5 ` B) <br />var3 = ((0.85 Ecc / B) - 0.38) <br />r_ra = (phiA 0.85 fc ` BA2 `((varl + var2)A0.5 - var3)) - (Axial LF) <br />use a reinforcement ratio that will result in r_ra equaling approximately 0: <br />rf_ratio = 0.0047 <br />r ra = 3.792 <br />As = 4.80 (in2) <br />SUMMARY OF LONGITUDINAL REINFORCEMENT <br />AASHTO 3.17.1.2 Steel Increase DESIGN AREA STEEL <br />Method 1 ACI Asl = 5.089in2 Asl_total= Asl ` 1.0 As I -total= 5.089in2 <br />Method 2 AASH As2 = 5.089in2 As2 total= As2 ` 1.0 As2 total= 5.089in2 <br />Method 3 IBC As3 = 2.545in2 Asa total= As3 ` 1.0 Asa total= 2.545in2 <br />Method 4 Whit As4 = 4.804in2 Aso total= As4 ` 1.3 Aso total= 6.390in2 <br />circumf = PI ` (B - 12 in) circumf = 75.398 in <br />32 <br />