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FTAO Visual&Size Determination:1 Opening <br /> Date: 7/18/2024 Engineer:OIL MAIN FRONT Job: 10052 <br /> Vwind: 2054 VEQ: -Wl,O6 r: <br /> V 1232 Opening 1 <br /> Li 6 ft ha1 2.833333 ft <br /> L2 1.875 ft ho1 3 ft <br /> hb1 3.833333 ft <br /> Lot 3 ft <br /> TD AR: 1.1:1 <br /> hwaU 9.667 ft Trib.Width of Dead Load: 2 ft Wall SW -252 Ibs <br /> Lwall 10.88 ft Length of Adjoining Wall: 4.8 ft <br /> 1. Hold-Down Forces: H=V*hwau/Lwau 1095 lb 6. Unit Shear Beside Opening: <br /> v1=(V/L)(L1+T1)/L1 156 plf <br /> 2. Unit Shear Above&Below Openings: v2=(V/L)(T2+L2+T3)/L2 156 plf <br /> First Opening: val=vbl=H/(hal+hbl) 164 plf <br /> Checkvl*Ll+v2*L2+v3*L3+v4*L4=V? 1232 OK <br /> 3. Total Boundary Foce Above&below Openings: 7 Resistance to Corner Forces: <br /> First Opening: 01=va1*Lol 493 Ibs R3=vl*Ll 939 Ibs <br /> R2=v2*L2 293 Ibs <br /> 4. Corner Forces: <br /> F1=01(L3)/(Ll+L2) 376 Ibs 8. Difference Corner Force+Resistance: <br /> F2=01(L2)/(L1+L2) 117 Ibs 11141 563 Ibs <br /> 11242 176 Ibs <br /> 9. Unit Shear in Corner Zones: <br /> vc1=(R1-F1)/L1 94 PLF <br /> 5. Tributary Length of Openings: vc2=(R2-F2)/L2 94 PLF <br /> T1=(L1*Lo1)/(Ll+L2) 2.29 ft <br /> T2=(L2*Lo1)/(L1+L2) 0.71 ft <br />