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0 <br />Install 11% L.F. 12" @ 0.3854 ft3/L,F. _ <br />Install 126 L.F. 12" a 0.7854 ft3/L,F. _ <br />Total Detention proviaed = <br />Required volume of det. _ <br />Fxcess volume provided = <br />Therefore O.K, <br />Sizing the Orifice <br />Q allowable = 0.56 c.f.s. <br />Utilizing the orifice equation Q= cdA 2gh <br />Assume h = 3.5' <br />Solving for A= 0,56 = 0.0602 1't,2 <br />cd g O.b2 . , <br />If 3 1/4" orifice = 0.0576 ft2 is used the h wi11 change <br />Therefore, solving for h-/ 0 1� = r �.56 Z� <br />lcdA� 2g 10.62 0,05i�4.4 <br />Orifice dia. = 3 1/4" <br />91,A9 ft3 <br />98.96 �ft3 <br />518,05 ft3 <br />504,17 ft3 <br />13.88 ft3 <br />= g ��n <br />= 3.82' = h <br />� <br />eees o � <br />4STE N6�1 � <br />)NAI E ..�1� <br />