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Total levels = I <br />At Roo( Levcl <br />W R= Roof weight x Arca + I/2 x Panition wcight x Arca + 2I I/2 x Gxt Wall weight x Perim x Height ] <br />IV„= I5.0 ps( x 8G0 sy.fl. + I/2 x 7.0 ps( x 8G0 sy.ft. + 2j 12 x 10.0 psf x 12G ft x 9A ftj = 27250 Ib <br />'fotal wcight = 27250 = 27250 Ibs <br />Compute structure perlod <br />Strucwrc lype: All nlhersrniclures <br />CT = 0.020 <br />Structurc height, h� = 9.00 R. <br />T,� = Cr(h„ )�r' = 0.020(9.00)"' = 0.103 sec. <br />Compute base shear <br />'The dcsign valuc o( C, is thc smallcr valuc o( <br />C, =/,S�s/R=1.00U.05)/G.50=0.IG21 EQ IG-35 <br />and <br />C, = l� S �i /(R T„ )= I.00(0.55)/l(G.50)(O.10)J = 0.8127 <br />but not Icss <br />C, =O.Od�1S��s/,=0.0�i4(1.05)(I.00)=0.WG3 <br />Thcreforc C,= O.IG2l <br />Design hasc shcar, V= C, tV = 0.1 G?(27250) = J-t I G Ibs (d.4 kips) <br />Vertical distribution of force <br />F,=C,.,V EQ IG-�il <br />whcrc <br />R',li; <br />C, � _ <br />� �V; /�; <br />HQ IG•3G <br />LQ IG-37 <br />CompWc distribution com�ncnt. k <br />k= I.0 for T<_ 0.5 seconds, anJ k= 2 lor T„>_ ? 5. Intemolaie k for T„ betwecn this range. <br />7;, = 0. � 04, k= I.00 <br />9.0 <br />SUM <br />27.3 k 2�i5 I.000 <br />?7 k 2�15 kdt <br />Jk <br />Fly` <br />0.16? <br />Compute dfaphragm shear(s) per ASCE 7-02 §9.5.2.6.4.4 <br />� <br />� r•,. <br />;_, <br />r�.� _ „ ��'�,� <br />� �''. <br />:_. <br />li�illl %. — �.�OS pa �� ����. <br />l:i(Lf �'ri — 0.��5 p� �. ����� <br />cu,oMon�cr, Date: AnalysisDocumenl: FOUNDATIONREPAIR <br />& ENGINEERING, INC 6/17/2005 <br />„„,��,..�,N,,��,�,.�u� Job Number. E6-427 <br />Page: 6 <br />