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; <br /> ��r�actural <br /> �ngineering & �esign �nc. <br /> _ 1815_Wriqht Av� La Verne CA 91750 Tel� 909�96 1351 Fax' 909 596 7186 i; <br /> BY� S•P- Projeot: MA.IESTIC GLOVE � <br /> _ Project#: LV-012418-2 � <br /> — i <br /> 'iransverse Brz�ce Configuration:7YPE 1 SELECTIVE RACK ' l <br /> " I <br /> � <br /> Section Prouerties � <br /> -- _ i <br /> Diagonal Niember= hiannibal 1-1/2x1-1/2x16ga Norizontal Member= Hannibal 1-1/2x1-1/2x16ga ; <br /> Area= 0.273 in^2 Area= 0.273 in^2 � <br /> � �t.500in� �1,5COm� <br /> r min= 0.4g6 in r min= 0.49b in <br /> Fy= 55,000 psi —�- Fy= 55,000 psi �-- � <br /> K= 1.0 �•5Oo��� K= 1.0 '.;ao�R i <br /> S2c= 1,92 � � ( <br /> i <br /> —�� �3--- 0.25 tn --�! � 0.25 tn �. <br /> I � <br /> Prame pimensions <br /> i <br /> Bottom Panei Height=H= 48.0 in Clear�epth=q-a�2= 38.0 in ! <br /> Frame Depth=D= q4.0 in X Braca= NQ i <br /> Column 1rVidth=B= 3.Q in rho= 1.00 1 <br /> I�i�gon�l hlember � <br /> .�-----� 0 <br /> �Load Case 6.•:(Ia-CI�2��fs�r9-�`[ ,85f0,X4Sds)�B*P�[0.7*rhoMEJ<=T.O,ASD hlethod <br /> i ° �I � <br /> Vtransverse= 2,510 ib vb I <br /> Vb=Vtransv*o.7�r(to= .25],p lb*0.7* 1 (kl/r)= (k*Ldiag)/r min � <br /> = 1,75T!b = (1 x 56.6 in/0.�496 in) <br /> Ldia9= [(D-B*2)^2+(H-6")^2]�1/2 = iih.i in Ldiag <br /> = 56.6 in �= Pi..2*���kUr)n2 � H <br /> Pmax= V+�(Ldiag/IJ)*0.75 = Z2,364 pSi Pn,ax i <br />� = i,s��►e �� <br /> axia!lo�d ar�diar1ossa/brace rnemher Since Fe<Fy/Z, 3��� I <br /> Pn= AREA*Fn Fn= Fe � <br /> = 0.273 in^2*22364 psi = 22 364 si B �� <br /> = 6,1051b � P 1 <br /> Tyr.ical Panel <br /> Confiauration � <br /> � <br /> 1 <br /> Pallow= Pn/S2 Checl<End kVeld � l <br /> = 6105 16/1.92 Lweld= 3.0 in j <br /> = 3,1$Q Ib Fu= 65 ksi i <br /> tmin= O.OfiO i� , <br /> Pn/Pallovd= U.53 <=1.0 OK � � * I <br /> . V�l21d C�pacity= OJ5 tmin L Fu/2.5 <br /> _ = 3,510 Ib OK � <br /> Horizmntal brace <br /> Yb=Ytrensv*0.7*rho= 1�75716 �--- - — v--- - � <br /> � <br /> � <br /> (k!/r)= (k*Lhoriz)/r min Fe= P��2*E/(�1/r)�Z Fy12= 27,50a psi � <br /> _ (1 x�kl in)/0.490 in = 37,OQ6 psi i <br /> = H8J in � <br /> 5inCe Fe�Fy/2,Fn-�y*(f-fy/4fe) Pn= AREA*Fn PalloNr= Pn/S2c I <br /> = 34,564 psi = 0.273in^2*34564 psi = 94361b/1.92 ,� <br /> = 9,436(b = 4,415 Ib f <br /> a- <br /> Pn/Pa!low= 0.�5 <=1.0 9K . ( <br /> --- — 'I <br /> II <br /> MAJESfICGLCJVE-fYPE I.xls pag� �� nf (� (,� ��2��2��8 !I <br /> f <br /> i <br /> _ __ ; <br />