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TSE Engineering Job#:�K3 <br /> By: <br /> Page:Z� <br /> HEADER <br /> INPUT: Uniform Loading Span Length <br /> w (DL) w(LL) L <br /> Roof (psf) 15 25 3 0 <br /> Tributary(it) 12 12 ft <br /> Wall (psf) 10 0 <br /> Tributary(ip 9 9 <br /> Floor (psf) 10 40 <br /> Tributary(fl) 5.5 5.5 <br /> Other(plf) 10 0 <br /> w(TL) 0 <br /> 335 520 855 0 <br /> pR plf plf <br /> RESULTS: <br /> VI (DL) Vr(DL) VI (LL) Vr(LL) VI (TL) Vr(TL) M (DL) M(LL) M (TL) <br /> 503 503 780 780 1283 1283 377 585 962 <br /> Ibs. Ibs. Ibs. Ibs. Ibs. Ibs. ft.lbs. R.Ibs. ft.lbs. <br /> DESIGN: <br /> MATERIAL Fb Fv Fc(perp) Ex10�`6 <br /> ManuELbr. Co 1.15 <br /> Timber CH 1 <br /> Dimen. Lbr. DFL#2 1170 180 625 1.6 Cf 1 <br /> psi psi psi psi Ci 1 <br /> b d A S I <br /> 3.5 725 25.38 30.7 111 <br /> in. in. in^2 in^3 in.^4 <br /> fv = 45 psi Brg.Lgth.= 0.049 ft R= 1.000 <br /> fb= 380 psi GL Cv= N/A R = N/A <br /> d (oy = 0.00 in. d (�y = 0.01 in. d (ry = 0.01 in. <br /> RATIOS OF ACTUAL TO ALLOWABLE RATIOS OF SPAN TO DEFLECTION <br /> fv/ Fv' = 022 L/ 6755 for LL <br /> fb I Fb' = 028 V 4109 for TL <br /> USE 4z8 DFLM2 <br /> v s.3 os <br />