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TSE Engineering Job k:72�3 <br /> By: <br /> Page:3b <br /> FLOOR BEAM <br /> INPUT: Uniform Loading Span Length <br /> w (DL) w(LL) L <br /> Roof (psf) 15 25 12 0 <br /> 7dbutary(H) 3 3 ft <br /> Wall (psf) 10 0 <br /> Ttlbutary(ft) 9 9 <br /> Floor (psf) 10 40 <br /> 7tlbutary(fl) 3 3 <br /> Other(plf) 10 0 <br /> w(TL) 0 <br /> 175 195 370 0 <br /> plf plf plf <br /> RESULTS: <br /> VI(DL) Vr(DL) VI(LL) Vr(LL) VI(TL) Vr(TL) M (DL) M (LL) M (TL) <br /> 1050 1050 1170 1170 2220 2220 3150 3510 6660 <br /> Ibs. Ibs. Ibs. Ibs. Ibs. Ibs. ft.lbs. ft.lbs. ft.lbs. <br /> DESIGN: <br /> MATERIAL Fb Fv Fc(perp) E x 10^6 <br /> Manuf.Lbc Co 1.15 <br /> 7imber DFLk2 875 170 625 1.3 CH 1 <br /> �imea Lbc Cr 1 <br /> psi psi psi psi Ci 1 <br /> b d A 5 I <br /> 5.5 9.5 5225 82.7 393 <br /> in. in. in^2 ia^3 in^4 <br /> fv= 55 psi Brg.Lgth.= 0.054 ft. CL= 1.000 <br /> fb= 970psi GLCv= N/A R = N/A <br /> d (o�)= 0.16 in. 4 (��)= 0.18 ia 4 (7y= 0.34 in. <br /> RATIOS OF ACTUAL TO ALLOWABLE RATIOS OF SPAN TO DEFLECTION <br /> fv/Fv' = 0.28 L/ 809 forLL <br /> fb/Fb'= 0.96 L/ 426 forTL <br /> USE 6x70DFL#2 <br /> (uR S�a�9<tu��1 <br /> I <br /> �3303 <br />