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7215 JUNIPER DR 2019-02-11
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7215 JUNIPER DR 2019-02-11
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2/11/2019 9:55:46 AM
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2/11/2019 9:55:39 AM
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Street Name
JUNIPER DR
Street Number
7215
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14 of 21 <br /> Corner Condition - Cantilever <br /> 4' cantilever w/ 8'-0"o.c. spacing <br /> Concrete Beam <br /> Lic.#:KW-06011993 Licensee:L120 Engineering and Design,KW-06011993 <br /> Description : 8ft+4ft cantliever Concrete Beam-Uniform Load(1-story Loading) <br /> CODE REFERENCES <br /> Calculations per ACI 318-14, IBC 2015, CBC 2016, ASCE 7-10 <br /> Load Combination Set : ASCE 7-10 <br /> Material Properties <br /> f'c1/2 2.50 ksi 4) Phi Values Flexure : 0.90 • <br /> fr= f'c 7.50 = 375.0 psi Shear : 0.750 ' <br /> 14) Density = 145.0 pcf R 1 = 0.850 <br /> X LtWt Facto = 1.0 <br /> Elastic Modulus 3,122.0 ksi Fy-Stirrups 40.0 ksi <br /> fy-Main Reba= 40.0 ksi E Stirrups 29,000.0 ksi <br /> E-Main Reba= 29,000.0 ksi Stirrup Bar Size# 3 <br /> Number of Resisting Legs Per Stirrup= 2 <br /> • • <br /> D 0.55 L 0.4 50.5 D 0.55 0.4L 0.5 <br /> 4'-0" 8'-0" <br /> Cross Section & Reinforcing Details <br /> Inverted Tee Section, Stem Width=8.0 in, Total Height=26.0 in, Top Flange Width= 12.0 in, Flange Thickness=8.0 in <br /> Span#1 Reinforcing.... <br /> 2-#4 at 3.0 in from Bottom, from 0.0 to 8.0 ft in this span 1-#4 at 11.0 in from Bottom,from 0.0 to 8.0 ft in this sp, <br /> 1-#4 at 3.0 in from Top, from 0.0 to 8.0 ft in this span <br /> Span#2 Reinforcing.... <br /> 2-#4 at 3.0 in from Bottom, from 0.0 to 8.0 ft in this span 1-#4 at 11.0 in from Bottom,from 0.0 to 8.0 ft in this sp, <br /> 1-#4 at 3.0 in from Top, from 0.0 to 8.0 ft in this span <br /> Applied Loads Service loads entered. Load Factors will be applied for calculations. <br /> Beam self weight calculated and added to loads <br /> Load for Span Number 1 <br /> Uniform Load : D=0.550, L=0.40, S=0.50 k/ft, Tributary Width= 1.0 ft, (Loading from above(1-story)-Uniform load) <br /> Load for Span Number 2 <br /> Uniform Load : D=0.550, L=0.40, S=0.50 k/ft, Tributary Width= 1.0 ft, (Loading from above(1-story)-Uniform load) <br /> DESIGN SUMMARY Desi.n OK <br /> Maximum Bending Stress Ratio = 0.694 : 1 Maximum Deflection <br /> Section used for this span Typical Section Max Downward Transient Deflection 0.000 in Ratio= 0<360. <br /> Mu:Applied -15.60 k-ft Max Upward Transient Deflection 0.000 in Ratio= 0<360. <br /> Mn*Phi:Allowable 22.494 k-ft Max Downward Total Deflection 0.002 in Ratio= 52234>=241 <br /> Max Upward Total Deflection 0.000 in Ratio= 999<240. <br /> Location of maximum on span 0.000 ft <br /> Span#where maximum occurs Span#2 <br /> Vertical Reactions Support notation:Far left is it- <br /> Load <br /> Load Combination Support 1 Support 2 Support 3 <br /> Overall MAXimum 13.200 4.400 <br /> Overall MINimum 3.600 1.200 <br /> +D+H 7.125 2.375 <br /> +D+L+H 10.725 3.575 <br />
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