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63 . 1 <br /> SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial <br /> Structural Engineers Job No. : 20-33 <br /> 12503 Bel-Red Road, Suite 100 Engr: : CT <br /> Bellevue, Washington 98005 Date: 10-20-2020 <br /> (425) 450-4075 Sheet No.: <br /> Description: Panel 6 - 42" leg Page 2 <br /> = _7 Number 5 Bars <br /> Results shown are for 42.00 inch wide section. <br /> CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) <br /> Service Load = 1.0D <br /> Service Defl. = N.A. in. Mu = 44.82 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 789.29 in-k <br /> CASE 1 @ Mid-ht., U = 1.4D ( M = = _ _ <br /> 5*P*e + P * Deflection. ) <br /> Service Load = 1.OD <br /> Service Defl. = 0.02 in. Mu = 30.11 in-k <br /> Ultimate Defl.- 0.18 in. Phi * Mn = 912.28 in-k <br /> CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.0L (M=P*e, No P*Delta) <br /> Service Load = 1.0D + 1.0(Lr or S or R) I: <br /> Service Defl. = N.A. in. Mu = 123.78 in-k <br /> Ultimate Defl.= N.A. in. Phi * Mn = 822.42 in-k t <br /> CASE 2 0 Mid-ht, U = 1.2D + 1.6(Lr or S or R) + 1.OL (M=.5*P*e + P*Delta.) <br /> Service Load = 1.OD + 1.0(Lr or S or R) <br /> Service Defl. = 0.07 in. Mu = 85.94 in-k <br /> Ultimate Defl.= 0.52 in. Phi * Mn - 927.43 in-k <br /> , • CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W <br /> Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.73 in. Mu = 407.55 in-k j <br /> Ultimate Defl.= 2.46 in. Phi * Mn = 927.43 in-k i..... <br /> CASE 4 U = 1.2➢ + 1.0W + 1.OL + 0.5 (Lr or S or R) <br /> Service load = 1.OD + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) <br /> Service Defl. = 0.75 in. Mu = 653.36 in-k <br /> Ultimate Defl.= 4.03 in. Phi * Mn = 903.24 in-k <br /> CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.OL + 0.2S <br /> Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) <br /> Service Defl. = 1.47 in. Mu = 852.25 in-k <br /> Ultimate Defl.= 5.21 in. Phi * Mn = 913.40 in-k <br /> =___ = <br /> CASE 6 U = 1.2D + 1.0W <br /> Service load = 1.OD + 0.6W <br /> Service Defl. = 1.05 in. Mu = 620.71 in-k <br /> Ultimate Defl.= 3.86 in. Phi * Mn - 892.21 in-k <br /> CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E <br /> Service load = (1 + 0.14Sds)D + 0.7E <br /> Service Defl. = 2.00 in. Mu = 837.09 in-k <br /> Ultimate Defl.= 5.14 in. Phi * Mn - 909.00 in-k ; [ <br /> CASE 8 U = 0.9D + 1.0W <br /> Service load = 0.6D + 0.6W <br /> Service Defl. = 0.96 in. Mu = 576.70 in-k <br /> Ultimate Defl.= 3.69 in. Phi * Mn = 861.99 in-k <br /> CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E <br /> Service load = (0.6 - 0.14 Sds)D + 0.7E <br /> Service Defl. = 1.84 in. Mu = 719.46 in-k s <br /> Ultimate Defl.= 4.67 in. Phi * Mn - 845.08 in-k l <br /> g <br /> S <br />