200 W MARINE VIEW DR ON TRAC LOGISTICS 2025-09-16

Ch 'AA SHUTLER CONSULTING ENGINEERS, INC. Job Name : Baywood Industrial Structural Engineers Job No. : 20-33 12503 Bel-Red Road, Suite 100 Engr: : CT Bellevue, Washington 98005 Date: : 10-20-2020 (425) 450-4075 Sheet No.: Description: Panel 6 - 32" leg Page 2 7 Number 5 Bars Results shown are for 32.00 inch wide section. CASE 1 @ Roof, U = 1.4D ( M = P*e -- No P * Deflection. ) Service Load = 1.UD Service Defl. = N.A. in. Mu = 41.84 in-k Ultimate Defl.= N.A. in. Phi * Mn = 774.30 in-k __CASE 1 @ Mid-ht., U = 1.4D ( M = .5*P*e + P * Deflection. ) (. Service Load = 1.0D Service Defl. = 0.03 in. Mu 28.38 in-k Ultimate Defl.= 0.19 in. Phi * Mn = 884.60 in-k =CASE 2 @ Roof, U = 1.2D + 1.6 (Lr or S or R) + 1.OL (M=P*e, No P*Delta) Service Load = 1.0D + 1.0(Lr or S or R) Service Defl. = N.A. in. Mu = 115.56 in-k Ultimate Defl.= N.A. in. Phi * Mn - 804.07 in-k CASE 2 @ Mid-ht, U = 1.2D + l.6(Lr or S or R) + 1.0L (M=.5*P*e + P*Delta.) Service Load = 1.0D + 1.0(Lr or S or R) Service Defi. = 0.08 in. Mu = 81.17 in-k Ultimate Defl.= 0.54 in. Phi * Mn = 898.15 in-k CASE 3 U = 1.2D + 1.6 ( Lr or S or R ) + 0.5W Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.93 in. Mu = 384.95 in-k Ultimate Defl.= 2.57 in. Phi * Mn = 898.15 in-k CASE 4 U = 1.2D + 1.0W + 1.0L + 0.5 (Lr or S or R) Service load = 1.0D + 0.75L + 0.75*0.6W + 0.75(Lr or S or R) Service Defl. = 0.95 in. Mu = 615.19 in-k Ultimate Defl.- 4.17 in. Phi * Mn = 876.52 in-k CASE 5 U = (1.2 + 0.2 Sds)D + 1.0E + 1.0L + 0.2S Service load = (1.0 + 0.1 Sds)D + 0.75L + 0.525E + 0.75(Lr or S or R) Service Defi. = 1.67 in. Mu = 803.47 in-k Ultimate Defl.= 5.41 in. Phi * Mn = 885.60 in-k CASE 6 U = 1.2D + 1.0W Service load = 1.0D + 0.6W Service Defl. = 1.24 in. Mu = 583.96 in-k Ultimate Defl.= 3.99 in. Phi * Mn = 866.65 in-k CASE 7 U = (1.2 + 0.2 Sds)D + 1.0E Service load = (1 + 0.14Sds)D + 0.7E Service Defl. = 2.18 in. Mu = 788.73 in-k Ultimate Defl.= 5.33 in. Phi * Mn = 881.66 in-k CASE 8 U = 0.9D + 1.0W Service load = 0.6D + 0.6W Service Defl. = 1.14 in. Mu = 540.75 in-k Ultimate Defl.- 3.78 in. Phi * Mn = 839.57 in-k CASE 9 U = (0.9 - 0.2 Sds)D + 1.0E Service load = (0.6 - 0.14 Sds)D + 0.7E Service Defl. = 1.99 in. Mu = 673.74 in-k Ultimate Defl.= 4.77 in. Phi * Mn = 824.40 in-k