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p <br />STORM <br />FOR <br />_ _25 + 2�� = 51.04 min. <br />Vs = 3607 T- 40 QoT <br />(�+ �' <br />= 3607 X 51.04 - 40 X 0.39 X 51.04 <br />5. 4+25 <br />= 1,624.89 ft.3/Ac. C <br />Vtotal = 0.9 X 0.57 X 1624.89 <br />= 834 ft.3 <br />Sizing the Orifice <br />Qallowable = 0.20 c.f.s. <br />Usin9 the orifice, equation Q= cdA 2gh <br />Assume h = 4 <br />Solving for A = = 0.20 <br />cd g • 0.62 . <br />= 0.0201 <br />= 1.92" orifice <br />If 2" orifice is.used = 0.0218', h will change <br />Sol vi ng for h=r.�) 22 <br />l 9 <br />r 0.20 Z 1 <br />\0.62 X 0.0218 64.4 <br />= 3.4' <br />Sizing the Detention System <br />Required storage = 834 ft.3 <br />Detention provided is as follows: <br />i. 30" pipe: 100 LF @ 7.068 ft.3/LF = <br />2. 12" pipe: 1Q0 LF @ 0.785 ft /LF = <br />3. MH type II - 48": 12.57 ft.3/�.f. X 2.4 v.f. _ <br />4. CBMH type II - 48": 12.57 ft. /v.f. X 3.0 v.f. _ <br />5. CB - lfi: 2.b7 ft.3/v.f. X 1.0 v.f. _ <br />Tn+il Storage Provided <br />R, �red Storage <br />f Provided <br />ICS' <br />RIC�- <br />WHSy/r • <br />os 2 <br />i: <br />968��p W <br />"'_'� ����i <br />,,.,., 6�.�P <br />706.86 ft.3 <br />78.40 ft.3 <br />42.74 ft.3 <br />37.11 ft.3 <br />2.67 ft. <br />868.48 ft.3 <br />- ii34.20 ft. <br />3�'�� <br />